project euler 36
来源:互联网 发布:软件升级服务 增值税 编辑:程序博客网 时间:2024/06/05 00:44
Problem 36
Double-base palindromes
The decimal number, 585 = 10010010012 (binary), is palindromic in both bases.
Find the sum of all numbers, less than one million, which are palindromic in base 10 and base 2.
(Please note that the palindromic number, in either base, may not include leading zeros.)
双进制回文数
十进制数585 = 10010010012(二进制表示),因此它在这两种进制下都是回文数。
找出所有小于一百万,且在十进制和二进制下均回文的数,并求它们的和。
(请注意,无论在哪种进制下,回文数均不考虑前导零。)
@Testpublic void test(){System.out.println(calculate(1000000));}public static long calculate(int upLimit){long sum = 0;for( int i = 1; i <= upLimit; i ++){if( isPalindromic( String.valueOf(i)) && isPalindromic( Integer.toBinaryString(i))){sum += i;System.out.println(i);}}return sum;}public static boolean isPalindromic(String val){char [] arr = new char[ val.length()];val.getChars(0, arr.length, arr, 0);for( int i = 0 ; i <= arr.length / 2; i ++){if( arr[i] != arr[ arr.length - 1 - i]){return false;}}return true;}
0 0
- Project Euler 36
- Project Euler Problem 36
- Project Euler problem 36
- Project Euler 36
- project euler Problem 36
- Python-Project Euler 36
- Project Euler 36~40
- project euler 36
- Project Euler 36
- project euler Problem 18 & 36
- Project Euler 36-40题
- Project Euler
- project euler
- Project Euler
- Project Euler:Problem 36 Double-base palindromes
- Project Euler .net
- Project Euler 0
- Project Euler 1-6
- project euler 35
- html5中js添加下拉菜单
- OC中的方法
- IOS OC 内存管理
- Android消息机制原理详解(Looper、Handler、MessageQueue)
- project euler 36
- 米4刷win10问题解答
- NYOJ 119士兵杀敌(三)【RMQ裸题】
- GCD Extreme 【FZU--1969】
- 大数据时代:生活、工作与思维的大变革(上)
- HDU 1086 You can Solve a Geometry Problem too
- Ubuntu15.04+caffe+cuda+cudnn+matlab
- 双向循环链表的实现
- 王道程序员求职宝典阅读笔记20151204