06 环形矩阵
来源：互联网 发布：英语教科书辅导软件 编辑：程序博客网 时间：2024/05/18 13:11
前言
这个概念貌似还不好说.., 搜了一下”环形矩阵”, 但是似乎没有这个概念
声明 : 这种矩阵可能不叫环形矩阵, 只不过是我将其称呼为环形矩阵
举个例子吧 :
参考代码
assume cs:code, ds:data, ss:stackdata segment notice db 'please input a number [press "q" to exit] : $ ' ; notice information matrix db 100 dup (0) ; save the data of matrix buffer db 3 ; user could input just two byte db 0 db 3 dup (0) input db 0 ; the width of matrix matrixWidth dw 10 ; the width of matrix resultWidth dw 42 ; the width of result matrix[for show to user] result db 420 dup(0) ; the result matrix[for show to user] tmp dw 2 dup(0) ; the temp memory to save the offset while change number to ascii br db 0aH, 0dH, '$'data endsstack segment db 200 dup (0)stack endscode segmentstart: mov ax, data mov ds, ax mov ax, stack mov ss, ax ; mov ah, 1 ; int 21H lea dx, notice ; output notice information call outputInfo lea dx, buffer ; let user input mov ah, 10 int 21H codeLoop1: call cls lea dx, br call outputInfo ; output a break line mov cl, buffer[1] mov ch, 0 cmp buffer[2], 'q' jz codeEnd mov di, cx ; 'mov di, cx+1' is error inc di mov al, 1 mov dx, 0 call getNumValue ; get the number value user inputed mov input, dl ; save it into input memory mov cl, input mov ch, 0 call calcMatrixData ; check the cx register!!!!!!!!!!!! , get the matrix's data call calcResultData ; get the result information call showResult ; show result information lea dx, notice ; output notice information call outputInfo lea dx, buffer ; let user input mov ah, 10 int 21H loop codeLoop1 codeEnd: mov ax, 4c00H ; return to cmd int 21HoutputInfo proc near ; the process to output something, the information save in begin with 'dx', end with '$' push ax mov ah, 9 int 21H pop ax retoutputInfo endp showResult proc near ; the process to show result information push di push dx mov di, 0 showResultLoop1: lea dx, result[di] call outputInfo ; output a row add di, 42 loop showResultLoop1 pop dx pop di retshowResult endp calcResultData proc near ; the process to get the result data[number value -> ascii] push si push di push cx ; the number value user inputed push ax ; assist register push bx mov si, 0 mov di, 0 mov ax, cx calcResultDataLoop1: push cx mov cx, ax calcResultDataLoop2: call getMatrixData ; get data from matrix by 'si' and 'di' push di call getResultIndexBySiAndDi ; get result index by 'si' and 'di' mov tmp, di inc di mov tmp[2], di call calcHalfWord ; put the matrix data input result matrix inc di ; add space, for view mov result[di], 32 inc di mov result[di], 32 pop di inc di loop calcResultDataLoop2 mov di, tmp[2] add di, 2 mov result[di], 0aH ; append the break line and '$' over symbol inc di mov result[di], 0dH inc di mov result[di], '$' inc si mov di, 0 pop cx loop calcResultDataLoop1 ; mov cx, ax ; mov di, 40 ; calcResultDataLoop3: ; inc di ; mov result[di], 0aH ; inc di ; mov result[di], 0dH ; add di, 42 ; loop calcResultDataLoop3 pop bx pop ax pop cx pop di pop si retcalcResultData endp getResultIndexBySiAndDi proc near ; get result matrix index by 'si' and 'di' push ax push bx mov ax, si mov bx, ds:[resultWidth] mul bl ; the result matrix width is 42 mov bx, ax mov ax, 4 mul di add ax, bx mov di, ax pop bx pop ax retgetResultIndexBySiAndDi endp getMatrixData proc near ; the function to get data of data matrix by 'si' and 'di', the data saved in 'bx' push di call getMatrixIndexBySiAndDi mov bl, matrix[di] mov bh, 0 pop di retgetMatrixData endp calcHalfByte proc near ; calc the bl [----just judge lower four bit----]' s corresponding ascii code, save in bl ; push bx ; bl record the data[need to be transfer] push cx ; record the offset to save in exp data segment cmp bl, 9 ja abc ; bl not bigger than 9 ; mov [exp+cx], bl+48 ; 1 ~ 8 add bl, 48 jmp calcHalfByteEnd abc: ; bl bigger than 9 ; mov [exp+cx], bl+87 ; A ~ F add bl, 87 calcHalfByteEnd: pop cx retcalcHalfByte endp calcHalfWord proc ; to calcute two hexadecimal number, number saved in bl, need to push two offset relative exp flag to save data push bx push di push dx push cx ; add sp, 4 ; mov stack pointer to save data offset, why there need just add 2 bit ? it just push ip in stack ? mov dx, bx mov cl, 4 ; calc the upper 4 bit shr bl, cl call calcHalfByte ; pop di mov di, ds:[tmp] ; the segment of tmp must match the left value[cx], use dw to define data mov ds:[result+di], bl mov bx, dx ; calc the lower 5 bit and bl, 15 call calcHalfByte ; pop di mov di, ds:[tmp+2] mov ds:[result+di], bl ; sub sp, 6 ; mov stack pointer to the real stack top ; why the value in stack changed ??? --2014.07.25 pop cx pop dx pop di pop bx retcalcHalfWord endp calcOneWord proc near ; to calcute two hexadecimal number, number saved in 'bx', 'di' saved the memory offset, push dx push di mov dx, bx mov cl, 8 ; calc the upper 8 bit of bx shr bx, cl inc di mov ds:[tmp], di inc di mov ds:[tmp+2], di call calcHalfWord mov bx, dx ; calc the lower 8 bit of bx mov bh, 0 inc di mov ds:[tmp], di inc di mov ds:[tmp+2], di call calcHalfWord pop di pop dx retcalcOneWord endpcalcMatrixData proc near ; put snake data matrix's data into matrix memory push si push di push dx ; the index 1, 2, 3, ... push cx ; the length user inputed push ax ; the assist register mov dx, 0 mov si, 0 mov di, 0 dec cx ; the number value user inputed cmp cx, 0 ; if user inputed is 1, jump to 'haveOneData' jz haveOneData calcMatrixDataLoop1: ; cmp cx, 0 ; jz haveOneData cmp cx, matrixWidth ; set cx bigger than f0 is overflow ja calcMatrixDataEnd ; if cx decrease to lower than 0,all data put completed , get to end mov ax, cx plusDi: call putData inc di inc dx loop plusDi mov cx, ax plusSi: call putData inc si inc dx loop plusSi mov cx, ax subDi: call putData dec di inc dx loop subDi mov cx, ax subSi: call putData dec si inc dx loop subSi inc si ; increase si, di to makes them at next position inc di mov cx, ax dec cx ; include loop cx will be decrease 2 loop calcMatrixDataLoop1 ; get there if cx is 0 haveOneData: ; it will get there whill cx is 0 call putData calcMatrixDataEnd: pop ax pop cx pop dx pop di pop si retcalcMatrixData endp putData proc near ; put data into memory, push di call getMatrixIndexBySiAndDi mov matrix[di], dl ; put the dx into memory pop di retputData endp getMatrixIndexBySiAndDi proc near ; get index of data matrix by 'si' and 'di' push ax push bx mov ax, si mov bx, ds:[matrixWidth] mul bl ; the matrix width is 10 add ax, di ; ax = 10 * si + di mov di, ax pop bx pop ax retgetMatrixIndexBySiAndDi endp getNumValue proc near ; get operand NumberValue by the number string in memory 1 2 3 -> 123 push di ; 'dx' save the ultamate result, 'di' save the last offset of input, 'al' is 1 base number, cx is the count of input push ax push cx getOperandValueLoop1: mov ah, buffer[di] call getNumValueByAscii push ax mul ah add dx, ax pop ax mov ah, 10 mul ah dec di loop getOperandValueLoop1 pop cx pop ax pop di retgetNumValue endpgetNumValueByAscii proc near ; get NumberValue by ascii cmp ah, 48 jae numFlag1 jmp getNumValueEnd numFlag1: cmp ah, 57 jbe numFlag2 jmp alphaFlag1 numFlag2: sub ah, 48 jmp getNumValueEnd alphaFlag1: cmp ah, 97 jae alphaFlag2 jmp getNumValueEnd alphaFlag2: cmp ah, 102 ja getNumValueEnd sub aH, 87 getNumValueEnd: retgetNumValueByAscii endp cls proc near ; to clear the screen push ax push bx push cx push dx mov ah,6 mov al,0 mov ch,0 mov cl,0 mov dh,20 mov dl,79 mov bh,7 int 10h pop dx pop cx pop bx pop ax retcls endpcode endsend start ; made by 970655147 --2014.07.30效果截图 :
0 0
- 06 环形矩阵
- 环形矩阵
- 环形矩阵
- 打印环形数字矩阵
- 环形打印矩阵
- 1-环形矩阵
- 环形（蛇形）矩阵
- 环形蛇形矩阵
- 环形打印矩阵
- C++环形矩阵填充实现
- 环形
- 打印回型数组 回型矩阵 环形数组
- POJ 1179 Polygon(环形DP 矩阵连乘)
- 打印回型数组-回型矩阵-环形数组
- 给定一个数n，输出n的环形矩阵
- 2017腾讯校招模拟题----环形蛇形矩阵
- 环形变换（矩阵快速幂+特殊矩阵加速）（北理16校赛）
- 打印环形数字矩阵，顺时针，边计算边打印，时间复杂度O(n^2)
- 项目开发文档之开发流程控制
- [原]CUDA中grid、block、thread、warp与SM、SP的关系
- 4-4 求自定类型元素的平均
- STM32的输入捕获
- 普通用户之间无法通过ssh协议进行切换（su）,即使输入正确的密码
- 06 环形矩阵
- Android内存优化（使用SparseArray和ArrayMap代替HashMap）
- Java 关键字-violate
- 大话设计模式 笔记2——策略模式
- centos 6.7 中文乱码 系统设为gbk
- 强大的浏览器插件vimperator
- MySql与SqlServer的一些常用用法的差别
- 虾米收藏音乐迁移到网易云音乐方法及工具
- Servlet基础(四：统计登录人数)
