MLlib里几个简单的分类模型(python)

# 这个数据集来自www.kaggle.com/c/stumbleupon/data, 用于预测网页是短暂存在还是长时间流行,这里我把它存放在hdfs文件系统内的/user/yy/stumbleupon/目录里rawData = sc.textFile("hdfs:///user/yy/stumbleupon/train_noheader.tsv")records = rawData.map(lambda line: line.split('\t'))records.first()# 每一条样本是一个网页的信息

[u’”http://www.bloomberg.com/news/2010-12-23/ibm-predicts-holographic-calls-air-breathing-batteries-by-2015.html“’,
u‘“4042”’,
u’”{“”title”“:”“IBM Sees Holographic Calls Air Breathing Batteries ibm sees holographic calls, air-breathing batteries”“,”“body”“:”“A sign stands outside the International Business Machines Corp IBM Almaden Research Center campus in San Jose California Photographer Tony Avelar Bloomberg Buildings stand at the International Business Machines Corp IBM Almaden Research Center campus in the Santa Teresa Hills of San Jose California Photographer Tony Avelar Bloomberg By 2015 your mobile phone will project a 3 D image of anyone who calls and your laptop will be powered by kinetic energy At least that s what International Business Machines Corp sees in its crystal ball The predictions are part of an annual tradition for the Armonk New York based company which surveys its 3 000 researchers to find five ideas expected to take root in the next five years IBM the world s largest provider of computer services looks to Silicon Valley for input gleaning many ideas from its Almaden research center in San Jose California Holographic conversations projected from mobile phones lead this year s list The predictions also include air breathing batteries computer programs that can tell when and where traffic jams will take place environmental information generated by sensors in cars and phones and cities powered by the heat thrown off by computer servers These are all stretch goals and that s good said Paul Saffo managing director of foresight at the investment advisory firm Discern in San Francisco In an era when pessimism is the new black a little dose of technological optimism is not a bad thing For IBM it s not just idle speculation The company is one of the few big corporations investing in long range research projects and it counts on innovation to fuel growth Saffo said Not all of its predictions pan out though IBM was overly optimistic about the spread of speech technology for instance When the ideas do lead to products they can have broad implications for society as well as IBM s bottom line he said Research Spending They have continued to do research when all the other grand research organizations are gone said Saffo who is also a consulting associate professor at Stanford University IBM invested 5 8 billion in research and development last year 6 1 percent of revenue While that s down from about 10 percent in the early 1990s the company spends a bigger share on research than its computing rivals Hewlett Packard Co the top maker of personal computers spent 2 4 percent last year At Almaden scientists work on projects that don t always fit in with IBM s computer business The lab s research includes efforts to develop an electric car battery that runs 500 miles on one charge a filtration system for desalination and a program that shows changes in geographic data IBM rose 9 cents to 146 04 at 11 02 a m in New York Stock Exchange composite trading The stock had gained 11 percent this year before today Citizen Science The list is meant to give a window into the company s innovation engine said Josephine Cheng a vice president at IBM s Almaden lab All this demonstrates a real culture of innovation at IBM and willingness to devote itself to solving some of the world s biggest problems she said Many of the predictions are based on projects that IBM has in the works One of this year s ideas that sensors in cars wallets and personal devices will give scientists better data about the environment is an expansion of the company s citizen science initiative Earlier this year IBM teamed up with the California State Water Resources Control Board and the City of San Jose Environmental Services to help gather information about waterways Researchers from Almaden created an application that lets smartphone users snap photos of streams and creeks and report back on conditions The hope is that these casual observations will help local and state officials who don t have the resources to do the work themselves Traffic Predictors IBM also sees data helping shorten commutes in the next five years Computer programs will use algorithms and real time traffic information to predict which roads will have backups and how to avoid getting stuck Batteries may last 10 times longer in 2015 than today IBM says Rather than using the current lithium ion technology new models could rely on energy dense metals that only need to interact with the air to recharge Some electronic devices might ditch batteries altogether and use something similar to kinetic wristwatches which only need to be shaken to generate a charge The final prediction involves recycling the heat generated by computers and data centers Almost half of the power used by data centers is currently spent keeping the computers cool IBM scientists say it would be better to harness that heat to warm houses and offices In IBM s first list of predictions compiled at the end of 2006 researchers said instantaneous speech translation would become the norm That hasn t happened yet While some programs can quickly translate electronic documents and instant messages and other apps can perform limited speech translation there s nothing widely available that acts like the universal translator in Star Trek Second Life The company also predicted that online immersive environments such as Second Life would become more widespread While immersive video games are as popular as ever Second Life s growth has slowed Internet users are flocking instead to the more 2 D environments of Facebook Inc and Twitter Inc Meanwhile a 2007 prediction that mobile phones will act as a wallet ticket broker concierge bank and shopping assistant is coming true thanks to the explosion of smartphone applications Consumers can pay bills through their banking apps buy movie tickets and get instant feedback on potential purchases all with a few taps on their phones The nice thing about the list is that it provokes thought Saffo said If everything came true they wouldn t be doing their job To contact the reporter on this story Ryan Flinn in San Francisco at rflinn bloomberg net To contact the editor responsible for this story Tom Giles at tgiles5 bloomberg net by 2015, your mobile phone will project a 3-d image of anyone who calls and your laptop will be powered by kinetic energy. at least that\u2019s what international business machines corp. sees in its crystal ball.”“,”“url”“:”“bloomberg news 2010 12 23 ibm predicts holographic calls air breathing batteries by 2015 html”“}”’,
u‘“business”’,
u‘“0.789131”’,
u‘“2.055555556”’,
u‘“0.676470588”’,
u‘“0.205882353”’,
u‘“0.047058824”’,
u‘“0.023529412”’,
u‘“0.443783175”’,
u‘“0”’,
u‘“0”’,
u‘“0.09077381”’,
u‘“0”’,
u‘“0.245831182”’,
u‘“0.003883495”’,
u‘“1”’,
u‘“1”’,
u‘“24”’,
u‘“0”’,
u‘“5424”’,
u‘“170”’,
u‘“8”’,
u‘“0.152941176”’,
u‘“0.079129575”’,
u‘“0”’]

from pyspark.mllib.regression import LabeledPoint # 标注点类型，（label, feature）通常feature是Vectors.dense类型from pyspark.mllib.linalg import Vectors# DenseVector类型的好处,这2行只是一个演示而已a = sc.parallelize([Vectors.dense(1,2),Vectors.dense(3,4)])a.sum() # 装着DenseVector类型向量的rdd,可以按列求值# def records_processing(record):#     trimmed = record.map(lambda e: e.replaceAll('\"', ''))#     label = int(trimmed[record.size - 1])#     features = trimmed[4 : record.size - 1].map(lambda d: 0.0 if d == '?' else float(d))#     return LabeledPoint(label, Vectors.dense(features))sizeAndData = records.map(lambda record : (len(record), map(lambda e: e.replace('\"', ''), record)))labelAndFeature = sizeAndData.map(lambda (size, data): (int(data[size-1]), map(lambda d: 0.0 if d == '?' else float(d), data[4: size-1])))data = labelAndFeature.map(lambda (label, feature): LabeledPoint(label, Vectors.dense(map(lambda d: 0.0 if d < 0 else d, feature))))data.first()

LabeledPoint(0.0, [0.789131,2.055555556,0.676470588,0.205882353,0.047058824,0.023529412,0.443783175,0.0,0.0,0.09077381,0.0,0.245831182,0.003883495,1.0,1.0,24.0,0.0,5424.0,170.0,8.0,0.152941176,0.079129575])

data.cache()data.count()

7395

from pyspark.mllib.classification import LogisticRegressionWithSGDfrom pyspark.mllib.classification import SVMWithSGDfrom pyspark.mllib.classification import NaiveBayesfrom pyspark.mllib.tree import DecisionTree# from pyspark.mllib.tree.configuration import Algo # from pyspark.mllib.tree.impurity import EntropynumIterations = 10maxTreeDepth = 5dataPoint = data.first()dataPoint

LabeledPoint(0.0, [0.789131,2.055555556,0.676470588,0.205882353,0.047058824,0.023529412,0.443783175,0.0,0.0,0.09077381,0.0,0.245831182,0.003883495,1.0,1.0,24.0,0.0,5424.0,170.0,8.0,0.152941176,0.079129575])

# 训练逻辑回归模型lrModel = LogisticRegressionWithSGD.train(data, numIterations)# 使用逻辑归回模型prediction = lrModel.predict(dataPoint.features)print "预测值：%d, 真实值：%d" % (prediction, dataPoint.label)# 看看逻辑回归整体的预测结果predictionsAndRealities = data.map(lambda point: lrModel.predict(point.features) == point.label)# 计算逻辑回归的准确率lrTotalCorrect = data.map(lambda point :                         1 if lrModel.predict(point.features) == point.label else 0                         ).sum()lrAccuracy = float(lrTotalCorrect) / data.count()print "逻辑回归准确率：", lrAccuracy# 计算PR(准确率-召回率)曲线下面积， 以及ROC(受试者工作特征曲线， 真阳性率-假阳性率)曲线下面积即AUCfrom pyspark.mllib.evaluation import BinaryClassificationMetricsscoreAndLabels = data.map(lambda point: (float(lrModel.predict(point.features)), point.label))metrics = BinaryClassificationMetrics(scoreAndLabels)print 'Area under PR: %2.4f%%, Area under ROC: %2.4f%%' % \    (metrics.areaUnderPR * 100, metrics.areaUnderROC * 100)

预测值：1, 真实值：0

逻辑回归准确率： 0.514672075727

Area under PR: 75.6759%, Area under ROC: 50.1418%

# 训练SVM模型svmModel = SVMWithSGD.train(data, numIterations)# 使用SVM模型prediction = svmModel.predict(dataPoint.features)print "预测值：%d, 真实值：%d" % (prediction, dataPoint.label)# 看看SVM整体的预测结果predictionsAndRealities = data.map(lambda point: svmModel.predict(point.features) == point.label)# 计算SVM的准确率svmTotalCorrect = data.map(lambda point :                         1 if svmModel.predict(point.features) == point.label else 0                         ).sum()svmAccuracy = float(svmTotalCorrect) / data.count()print "SVM准确率：", svmAccuracy# 计算PR(准确率-召回率)曲线下面积， 以及ROC(受试者工作特征曲线， 真阳性率-假阳性率)曲线下面积即AUCscoreAndLabels = data.map(lambda point: (float(svmModel.predict(point.features)), point.label))metrics = BinaryClassificationMetrics(scoreAndLabels)print 'Area under PR: %2.4f%%, Area under ROC: %2.4f%%' % \    (metrics.areaUnderPR * 100, metrics.areaUnderROC * 100)

预测值：1, 真实值：0

SVM准确率： 0.514672075727

Area under PR: 75.6759%, Area under ROC: 50.1418%

# 训练朴素贝叶斯模型nbModel = NaiveBayes.train(data)# 使用朴素贝叶斯模型prediction = nbModel.predict(dataPoint.features)print "预测值：%d, 真实值：%d" % (prediction, dataPoint.label)# 看看朴素贝叶斯整体的预测结果predictionsAndRealities = data.map(lambda point: nbModel.predict(point.features) == point.label)# 计算朴素贝叶斯的准确率nbTotalCorrect = data.map(lambda point :                         1 if nbModel.predict(point.features) == point.label else 0                         ).sum()nbAccuracy = float(nbTotalCorrect) / data.count()print "朴素贝叶斯准确率：", nbAccuracy# 计算PR(准确率-召回率)曲线下面积， 以及ROC(受试者工作特征曲线， 真阳性率-假阳性率)曲线下面积即AUCfrom pyspark.mllib.evaluation import BinaryClassificationMetricsscoreAndLabels = data.map(lambda point: (float(nbModel.predict(point.features)), point.label))metrics = BinaryClassificationMetrics(scoreAndLabels)print 'Area under PR: %2.4f%%, Area under ROC: %2.4f%%' % \    (metrics.areaUnderPR * 100, metrics.areaUnderROC * 100)

预测值：1, 真实值：0

朴素贝叶斯准确率： 0.580392156863

Area under PR: 68.0851%, Area under ROC: 58.3559%

# 训练决策树模型dtModel = DecisionTree.trainClassifier(data, 2, {})# 使用决策树模型prediction = dtModel.predict(dataPoint.features)print "预测值：%d, 真实值：%d" % (prediction, dataPoint.label)# 看看决策树整体的预测结果, 决策树模型只能在主节点上使用predictions = dtModel.predict(data.map(lambda point: point.features))results = predictions.zip(data.map(lambda point: point.label))# 计算决策树的准确率dtTotalCorrect = results.filter(lambda (real, pred): pred == real).count()dtAccuracy = float(dtTotalCorrect) / data.count()print "决策树准确率：", dtAccuracy# 计算PR(准确率-召回率)曲线下面积， 以及ROC(受试者工作特征曲线， 真阳性率-假阳性率)曲线下面积即AUCmetrics = BinaryClassificationMetrics(results)print 'Area under PR: %2.4f%%, Area under ROC: %2.4f%%' % \    (metrics.areaUnderPR * 100, metrics.areaUnderROC * 100)

预测值：0, 真实值：0

决策树准确率： 0.648275862069

Area under PR: 74.2894%, Area under ROC: 64.8916%

# 上面的结果跟随机差不多，原因是我们仅仅只是把数据送入模型# 改进模型性能以及参数调优# from pyspark.mllib.linalg.distributed import RowMatrixmatrix = data.map(lambda point: point.features)print "矩阵的第一行：\n", matrix.first()result = matrix.stats()print "矩阵各列的平均值：\n", result.mean()print "矩阵各列的最小值：\n", result.min()print "矩阵各列的最大值：\n", result.max()print "矩阵各列的标准差：\n", result.stdev()print "矩阵各列的方差：\n", result.variance()

矩阵的第一行：
[0.789131,2.055555556,0.676470588,0.205882353,0.047058824,0.023529412,0.443783175,0.0,0.0,0.09077381,0.0,0.245831182,0.003883495,1.0,1.0,24.0,0.0,5424.0,170.0,8.0,0.152941176,0.079129575]

矩阵各列的平均值：
[0.412258052995,2.76182319199,0.468230473286,0.214079926384,0.092062360719,0.0492621604391,2.25510345221,0.000914886880189,0.0,0.0564227449842,0.02123056119,0.233778176655,0.369015325398,0.615551048005,0.66031102096,30.0770791075,0.0397565922921,5716.59824206,178.754563895,4.96064908722,0.17286405047,0.101220791893]

矩阵各列的最小值：

[ 0. 0. 0. 0. 0. 0. 0.
0. 0. 0. 0. 0.04556422 0. 0.
0. 0. 0. 0. 1. 0. 0.
0. ]

矩阵各列的最大值：

[ 9.99426000e-01 3.63000000e+02 1.00000000e+00 1.00000000e+00
9.80392157e-01 9.80392157e-01 2.10000000e+01 2.50000000e-01
0.00000000e+00 4.44444444e-01 1.00000000e+00 7.16883117e-01
1.13333333e+02 1.00000000e+00 1.00000000e+00 1.00000000e+02
1.00000000e+00 2.07952000e+05 4.99700000e+03 2.20000000e+01
1.00000000e+00 1.00000000e+00]

矩阵各列的标准差：

[ 3.31251568e-01 8.61920979e+00 2.03119645e-01 1.46732834e-01
9.59717238e-02 7.26238264e-02 5.70392733e+00 7.42829375e-03
0.00000000e+00 4.14428371e-02 1.44152088e-01 5.24830153e-02
1.87878356e+00 4.86464752e-01 4.73603607e-01 2.03917219e+01
1.95386810e-01 8.87483231e+03 1.79454063e+02 3.23289275e+00
1.83273269e-01 7.92255262e-02]

矩阵各列的方差：
[0.109727601589,74.2907773273,0.041257590017,0.0215305244407,0.00921057176901,0.00527422015895,32.5347869854,5.51795480353e-05,0.0,0.00171750875055,0.0207798244616,0.00275446689512,3.52982764865,0.236647955305,0.224300376559,415.822321151,0.0381760056614,78762648.5733,32203.7608565,10.4515955219,0.0335890912886,0.00627668399539]

from pyspark.mllib.feature import StandardScaler# 第一个True表示均值正则化（每个值减去均值），第二个True表示正则化标准差（每个值除以标准差进行缩放）scaler = StandardScaler(withMean=True, withStd=True).fit(matrix)scaledData = scaler.transform(matrix)scaledData = data.map(lambda lp: lp.label).zip(scaledData).map(lambda (label, feature): LabeledPoint(label, feature))print "标准化前：\n", data.first().featuresprint "标准化后：\n", scaledData.first().featuresimport numpy as npvector = np.array(matrix.first())mean = np.array(result.mean())stdev = np.array(result.stdev())print "手动标准化：\n", (vector - mean) / stdev

标准化前：
[0.789131,2.055555556,0.676470588,0.205882353,0.047058824,0.023529412,0.443783175,0.0,0.0,0.09077381,0.0,0.245831182,0.003883495,1.0,1.0,24.0,0.0,5424.0,170.0,8.0,0.152941176,0.079129575]

标准化后：
[1.1376473365,-0.0819355716929,1.02513981289,-0.0558635644254,-0.468893253129,-0.354305326308,-0.317535217236,-0.123154125351,0.0,0.828822173315,-0.147268943346,0.229639823578,-0.194331667814,0.790238049918,0.717194729453,-0.297996816496,-0.20346257793,-0.0329672096969,-0.0487811297558,0.940069975117,-0.108698488525,-0.278820782314]

手动标准化：

[ 1.13772426 -0.08194111 1.02520913 -0.05586734 -0.46892496 -0.35432928
-0.31755669 -0.12316245 nan 0.82887822 -0.1472789 0.22965535
-0.19434481 0.79029149 0.71724323 -0.29801697 -0.20347634 -0.03296944
-0.04878443 0.94013354 -0.10870584 -0.27883964]

# 用标准化后的数据重新训练模型，不训练决策树和朴素贝叶斯，因为他俩不受特征标准化的影响# 训练逻辑回归模型lrModelScaled = LogisticRegressionWithSGD.train(scaledData, numIterations)# 看看逻辑回归整体的预测结果lrTotalCorrectScaled = scaledData.filter(lambda point: lrModelScaled.predict(point.features) == point.label).count()print "预测正确的样本个数", lrTotalCorrectScaled# 计算逻辑回归的准确率lrAccuracyScaled = float(lrTotalCorrectScaled) / data.count()print "逻辑回归准确率：", lrAccuracyScaled# 计算PR(准确率-召回率)曲线下面积， 以及ROC(受试者工作特征曲线， 真阳性率-假阳性率)曲线下面积即AUClrPredictionsVsTrue = scaledData.map(lambda point: (float(lrModelScaled.predict(point.features)), point.label))lrMetricsScaled = BinaryClassificationMetrics(lrPredictionsVsTrue)print 'Area under PR: %2.4f%%, Area under ROC: %2.4f%%' % \    (lrMetricsScaled.areaUnderPR * 100, lrMetricsScaled.areaUnderROC * 100)

预测正确的样本个数 4609

逻辑回归准确率： 0.623258958756

Area under PR: 73.0204%, Area under ROC: 62.2292%

# 考虑网页的类别特征，比如这个网页是属于sports类还是business类categories = dict(records.map(lambda record: record[3].replace('\"', '')).distinct().zipWithIndex().collect())print categoriesnumCategories = len(categories)print numCategoriescategories = sc.broadcast(categories)numCategories = sc.broadcast(numCategories)

{u’gaming’: 7, u’recreation’: 0, u’business’: 1, u’computer_internet’: 2, u’unknown’: 8, u’culture_politics’: 3, u’science_technology’: 9, u’law_crime’: 4, u’sports’: 10, u’religion’: 11, u’weather’: 12, u’health’: 5, u’?’: 6, u’arts_entertainment’: 13}
14

def buildCategoriesVector(data):    vector = [0] * numCategories.value    vector[categories.value[data[3]]] = 1    return vector + data[4:-1]sizeAndData = records.map(lambda record : (len(record), map(lambda e: e.replace('\"', ''), record)))labelAndFeature = sizeAndData.map(lambda (size, data): (int(data[-1]), map(lambda d: 0.0 if d == '?' else float(d), buildCategoriesVector(data))))dataCategories = labelAndFeature.map(lambda (label, feature): LabeledPoint(label, Vectors.dense(map(lambda d: 0.0 if d < 0 else d, feature))))dataPointCats = dataCategories.first()print labelAndFeature.first()print dataPointCats 

(0, [0.0, 1.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.789131, 2.055555556, 0.676470588, 0.205882353, 0.047058824, 0.023529412, 0.443783175, 0.0, 0.0, 0.09077381, 0.0, 0.245831182, 0.003883495, 1.0, 1.0, 24.0, 0.0, 5424.0, 170.0, 8.0, 0.152941176, 0.079129575])

(0.0,[0.0,1.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.0,0.789131,2.055555556,0.676470588,0.205882353,0.047058824,0.023529412,0.443783175,0.0,0.0,0.09077381,0.0,0.245831182,0.003883495,1.0,1.0,24.0,0.0,5424.0,170.0,8.0,0.152941176,0.079129575])

# 标准化转换labels = dataCategories.map(lambda lp: lp.label)featuresMatrix = dataCategories.map(lambda lp: lp.features)scalerCats = StandardScaler(withMean=True, withStd=True).fit(featuresMatrix)scaledDataCats = scalerCats.transform(featuresMatrix).zip(labels).map(lambda (features, label): LabeledPoint(label, features))scaledDataCats.first()

LabeledPoint(0.0, [-0.446421204794,2.72073665645,-0.204182210579,-0.220526884579,-0.0648775723926,-0.270999069693,-0.680752790425,-0.101894690972,-0.028494000387,-0.201654052319,-0.232727977095,-0.0991499193088,-0.0232621058984,-0.381813223243,1.1376473365,-0.0819355716929,1.02513981289,-0.0558635644254,-0.468893253129,-0.354305326308,-0.317535217236,-0.123154125351,0.0,0.828822173315,-0.147268943346,0.229639823578,-0.194331667814,0.790238049918,0.717194729453,-0.297996816496,-0.20346257793,-0.0329672096969,-0.0487811297558,0.940069975117,-0.108698488525,-0.278820782314])

lrModelScaledCats = LogisticRegressionWithSGD.train(scaledDataCats, numIterations)# 看看逻辑回归整体的预测结果lrTotalCorrectScaledCats = scaledDataCats.filter(lambda point: lrModelScaledCats.predict(point.features) == point.label).count()print "预测正确的样本个数", lrTotalCorrectScaledCats# 计算逻辑回归的准确率lrAccuracyScaledCats = float(lrTotalCorrectScaledCats) / scaledDataCats.count()print "逻辑回归准确率：", lrAccuracyScaledCats# 计算PR(准确率-召回率)曲线下面积， 以及ROC(受试者工作特征曲线， 真阳性率-假阳性率)曲线下面积即AUClrPredictionsVsTrue = scaledDataCats.map(lambda point: (float(lrModelScaledCats.predict(point.features)), point.label))lrMetricsScaledCats = BinaryClassificationMetrics(lrPredictionsVsTrue)print 'Area under PR: %2.4f%%, Area under ROC: %2.4f%%' % \    (lrMetricsScaledCats.areaUnderPR * 100, lrMetricsScaledCats.areaUnderROC * 100)

预测正确的样本个数 4928

逻辑回归准确率： 0.666396213658

Area under PR: 75.8535%, Area under ROC: 66.6127%

# 只使用1-of-k编码的类别特征def onlyCategoriesVector(data):    vector = [0] * numCategories.value    vector[categories.value[data[3]]] = 1    return vectorsizeAndData = records.map(lambda record : (len(record), map(lambda e: e.replace('\"', ''), record)))labelAndFeature = sizeAndData.map(lambda (size, data): \                                  (int(data[-1]), map(lambda d: 0.0 if d == '?' else float(d), onlyCategoriesVector(data))))dataNB = labelAndFeature.map(lambda (label, feature): \                             LabeledPoint(label, Vectors.dense(map(lambda d: 0.0 if d < 0 else d, feature))))# 训练朴素贝叶斯模型nbModelCats = NaiveBayes.train(dataNB)# 计算朴素贝叶斯的准确率nbTotalCorrectCats = dataNB.map(lambda point :                         1 if nbModelCats.predict(point.features) == point.label else 0                         ).sum()nbAccuracyCats = float(nbTotalCorrectCats) / dataNB.count()print "朴素贝叶斯准确率：", nbAccuracyCatsnbPredictionsVsTrueCats = dataNB.map(lambda point: (float(nbModelCats.predict(point.features)), point.label))nbMetricsCats = BinaryClassificationMetrics(nbPredictionsVsTrueCats)print 'Area under PR: %2.4f%%, Area under ROC: %2.4f%%' % \    (nbMetricsCats.areaUnderPR * 100, nbMetricsCats.areaUnderROC * 100)

朴素贝叶斯准确率： 0.609601081812

Area under PR: 74.0522%, Area under ROC: 60.5138%