hdu1228——A+B

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A + B

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 14346 Accepted Submission(s): 8511

Problem Description

读入两个小于100的正整数A和B,计算A+B.
需要注意的是:A和B的每一位数字由对应的英文单词给出.

Input

测试输入包含若干测试用例,每个测试用例占一行,格式为"A + B =",相邻两字符串有一个空格间隔.当A和B同时为0时输入结束,相应的结果不要输出.

Output

对每个测试用例输出1行,即A+B的值.

Sample Input

one + two =three four + five six =zero seven + eight nine =zero + zero =

Sample Output

水题一道，map存对应值即可！

#include<iostream>#include<map>using namespace std;int add(string a,string b){map<string,int> num;num["one"]=1;num["two"]=2;num["three"]=3;num["four"]=4;num["five"]=5;num["six"]=6;num["seven"]=7;num["eight"]=8;num["nine"]=9;num["zero"]=0;int i,m=0,n=0;string tem;for(i=0;i<a.size();i++){if(a[i]==' ') {m=m*10+num[tem];tem.clear();}else tem+=a[i];}tem.clear();for(i=0;i<b.size();i++){if(b[i]==' ') {n=n*10+num[tem];tem.clear();}else tem+=b[i];}return m+n;}int main(){string str;while(getline(cin,str)){int len=str.size();string a,b;int i,k;for(i=0;i<len;i++){if(str[i]=='+') break;a+=str[i];}for(k=i+2;k<len;k++){if(str[k]=='=') break;b+=str[k];}if(add(a,b)==0) break; else cout<<add(a,b)<<endl;}return 0;}

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