[LeetCode] Integer to Roman 解题报告

来源:互联网 发布:ug10.0加工编程铣平面 编辑:程序博客网 时间:2024/05/14 14:32

Given an integer, convert it to a roman numeral.
Input is guaranteed to be within the range from 1 to 3999.

» Solve this problem

[解题思路]
这道题主要就在于如何处理每一位digit,并且按照区间不同处理:
1<=digit <=3
digit =4
digit = 5
5<digit<=8
digit =9

[Code]

1:  string intToRoman(int num) {  
2: // Start typing your C/C++ solution below
3: // DO NOT write int main() function
4: char symbol[7] = { 'I','V','X', 'L','C', 'D','M'};
5: string roman;
6: int scale = 1000;
7: for(int i =6; i>=0; i-=2)
8: {
9: int digit = num/scale;
10: if(digit != 0)
11: {
12: if(digit <= 3)
13: {
14: roman.append(digit, symbol[i]);
15: }
16: else if(digit ==4)
17: {
18: roman.append(1, symbol[i]);
19: roman.append(1, symbol[i+1]);
20: }
21: else if(digit ==5)
22: {
23: roman.append(1, symbol[i+1]);
24: }
25: else if(digit <=8)
26: {
27: roman.append(1, symbol[i+1]);
28: roman.append(digit-5, symbol[i]);
29: }
30: else if(digit ==9)
31: {
32: roman.append(1, symbol[i]);
33: roman.append(1, symbol[i+2]);
34: }
35: }
36: num = num%scale;
37: scale/=10;
38: }
39: return roman;
40: }

0 0
原创粉丝点击