Leetcode 35 - Search Insert Position

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

You may assume no duplicates in the array.

Here are few examples.
[1,3,5,6], 5 → 2
[1,3,5,6], 2 → 1
[1,3,5,6], 7 → 4
[1,3,5,6], 0 → 0

思路：仍然是binary search。

class Solution {public:    int searchInsert(vector<int>& nums, int target) {        int left = 0;        int right = nums.size()-1;        int mid;        //Binary Search        while(left<=right){            mid = (left+right)/2;            if(nums[mid]==target){                return mid;            }            if(nums[mid]>target){                right = mid-1;            }            if(nums[mid]<target){                left = mid+1;            }        }        return left;    }};