HDOJ 2055 An easy problem

Problem Description
we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, … f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

Input
On the first line, contains a number T.then T lines follow, each line is a case.each case contains a letter and a number.

Output
for each case, you should the result of y+f(x) on a line.

Sample Input
6
R 1
P 2
G 3
r 1
p 2
g 3

Sample Output
19
18
10
-17
-14
-4

题意：we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, … f(Z) = 26, f(z) = -26;Give you a letter x and a number y , you should output the result of y+f(x)..

import java.util.Scanner;public class Main {    public static void main(String[] args) {        Scanner sc = new Scanner(System.in);        String lowerCase = "0abcdefghijklmnopqrstuvwxyz";        String capital = "1ABCDEFGHIJKLMNOPQRSTUVWXYZ";        int n =sc.nextInt();        //sc.next();        while(n-->0){            String strs = sc.next();            //System.out.println(strs);            int y = sc.nextInt();            char x = strs.charAt(0);            //strs = strs.substring(2);            //int y = Integer.parseInt(strs,10);            //System.out.println(x);            //System.out.println(y);            int g=0,h=0;            for(int i=1;i<lowerCase.length();i++){                if(x==lowerCase.charAt(i)){                    g=-i;                    break;                }            }            for(int i=1;i<capital.length();i++){                if(x==capital.charAt(i)){                    h=i;                    break;                }            }            System.out.println(y+g+h);        }    }}