Codeforces Round #202 (Div. 2)（A）贪心

A. Cinema Line

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

The new "Die Hard" movie has just been released! There are n people at the cinema box office standing in a huge line. Each of them has a single 100, 50 or 25 ruble bill. A "Die Hard" ticket costs 25 rubles. Can the booking clerk sell a ticket to each person and give the change if he initially has no money and sells the tickets strictly in the order people follow in the line?

Input

The first line contains integer n (1 ≤ n ≤ 105) — the number of people in the line. The next line contains n integers, each of them equals25, 50 or 100 — the values of the bills the people have. The numbers are given in the order from the beginning of the line (at the box office) to the end of the line.

Output

Print "YES" (without the quotes) if the booking clerk can sell a ticket to each person and give the change. Otherwise print "NO".

Sample test(s)

input

425 25 50 50

output

YES

input

225 100

output

NO

input

450 50 25 25

output

NO

题意：有一群人排队买票，一张票25块钱，开始售票处没有钱，每个人持着25,50,100的面值去购票，问售票处能否完成这个队伍的购票

题解：直接模拟一下就好

#include <set>#include <map>#include <list> #include <cmath> #include <queue> #include <vector>#include <cstdio> #include <string> #include <cstring>#include <iomanip> #include <iostream> #include <sstream>#include <algorithm>#define  LL long long #define  N 100005using namespace std; int main(){#ifdef CDZSCfreopen("i.txt","r",stdin);#endifint n,x;while(~scanf("%d",&n)){int ok=1;int a25=0;int a50=0;int a100=0;for(int i=0;i<n;i++){scanf("%d",&x);x-=25;if(x==0){a25++;x=0;}if(x==25&&a25>0){x=0;a50++;a25--;}if(x==75){if(a50>0&&a25>0&&x){x=0;a50--;a25--;}if(x&&a25>=3){a25-=3;x=0;}}if(x>0)ok=0;}puts(ok?"YES":"NO");}return 0;}