1003. 我要通过！(20)

来源：互联网发布：淘宝提前收款怎么用编辑：程序博客网时间：2024/04/26 15:29

题目：http://www.patest.cn/contests/pat-b-practise/1003

代码：

#include <stdio.h>#include <string.h>int main(){    char a[10][100];    int n,i,j,k;    //pnum,tnum是p和t的个数，bunm_A为p之前A的个数，mnum_A为p与t之间A的个数，anum_A为t之后A的个数    int pnum,tnum,bnum_A,mnum_A,anum_A;    int pi,ti;    scanf("%d",&n);    for (i=0;i<n;i++)        scanf("%s",a[i]);    for (i=0;i<n;i++)    {        j = 0;        pnum = 0;        tnum = 0;        k = 0;        while( a[i][j]!='\0')        {            if ( a[i][j]!='P'&&a[i][j]!='A'&&a[i][j]!='T')            {                k = 1;                break;            }            else if ( a[i][j]=='P')            {                pnum++;                pi = j;            }            else if ( a[i][j]=='T')            {                tnum++;                ti = j;            }            j++;        }        if (pnum!=1||tnum!=1||k == 1)            printf("NO\n");        else        {            bnum_A = pi;            mnum_A = ti-pi-1;            anum_A = j-ti-1;            //PT的情况            if ((ti-pi)==1)                printf("NO\n");            //判断条件为符合条件的规律            else if (bnum_A*mnum_A==anum_A)                printf("YES\n");            else                printf("NO\n");        }    }    return 0;}

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