1058. A+B in Hogwarts (20)

来源:互联网 发布:拍摄后期制作软件 编辑:程序博客网 时间:2024/05/10 14:55

1058. A+B in Hogwarts (20)

时间限制
50 ms
内存限制
65536 kB
代码长度限制
16000 B
判题程序
Standard
作者
CHEN, Yue

If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to compute A+B where A and B are given in the standard form of "Galleon.Sickle.Knut" (Galleon is an integer in [0, 107], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

Input Specification:

Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

Output Specification:

For each test case you should output the sum of A and B in one line, with the same format as the input.

Sample Input:
3.2.1 10.16.27
Sample Output:
14.1.28
#include <iostream>#include <algorithm>#include <stdio.h>#include <map>using namespace std;int main() {    string str1,str2;    int a1,a2,a3,b1,b2,b3,a,b,c;    cin>>str1>>str2;    sscanf(str1.c_str(),"%d.%d.%d",&a1,&a2,&a3);    sscanf(str2.c_str(),"%d.%d.%d",&b1,&b2,&b3);    a=a1+b1;    b=a2+b2;    c=a3+b3;    b=b+c/29;    c=c%29;    a=a+b/17;    b=b%17;    printf("%d.%d.%d\n",a,b,c);    return 0;}


0 0
原创粉丝点击