HDU2001计算两点间的距离（C,Java用DecimalFormat格式控制）

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计算两点间的距离

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 162829 Accepted Submission(s): 57801

Problem Description

输入两点坐标（X1,Y1）,（X2,Y2）,计算并输出两点间的距离。

Input

输入数据有多组，每组占一行，由4个实数组成，分别表示x1,y1,x2,y2,数据之间用空格隔开。

Output

对于每组输入数据，输出一行，结果保留两位小数。

Sample Input

0 0 0 10 1 1 0

Sample Output

1.001.41

Author

lcy

Source

C语言程序设计练习（一）

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C语言AC代码：

#include <stdio.h>#include <math.h>int main(){    double x1,y1,x2,y2,d;    while (scanf("%lf %lf %lf %lf",&x1,&y1,&x2,&y2)!=EOF)    {        d=sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2));        printf("%.2lf\n",d);    }    return 0;}

Java AC代码：

import java.text.DecimalFormat;import java.util.Scanner;public class Main {public static void main(String[] args) {Scanner sc = new Scanner(System.in);while(sc.hasNext()){double x1 = sc.nextDouble();double y1 = sc.nextDouble();double x2 = sc.nextDouble();double y2 = sc.nextDouble();double a =Math.sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2));DecimalFormat df = new DecimalFormat("#0.00");System.out.println(df.format(a));}}}

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