38. Count and Say【E】【79】【leetcode】
来源:互联网 发布:淘宝的拍照权限设置 编辑:程序博客网 时间:2024/06/05 17:00
The count-and-say sequence is the sequence of integers beginning as follows:1, 11, 21, 1211, 111221, ...
1
is read off as "one 1"
or 11
.11
is read off as "two 1s"
or 21
.21
is read off as "one 2
, then one 1"
or 1211
.
Given an integer n, generate the nth sequence.
Note: The sequence of integers will be represented as a string.
Subscribe to see which companies asked this question
就是简简单单按照这个过程复制一遍
class Solution(object): def countAndSay(self, n): res = '1' for i in xrange(n - 1): #print i,res cur = res[0] count = 1 t_res = '' for j in res[1:]: if j == cur: count += 1 continue else: t_res += str(count) + cur cur = j count = 1 t_res += str(count) + cur #print t_res,'\n' res = t_res return res
0 0
- 38. Count and Say【E】【79】【leetcode】
- [LeetCode]38.Count and Say
- LeetCode --- 38. Count and Say
- LeetCode 38.Count and Say
- [Leetcode] 38. Count and Say
- 38. Count and Say LeetCode
- Leetcode 38. Count and Say
- leetcode 38. Count and Say
- [leetcode] 38. Count and Say
- LeetCode-38.Count and Say
- LeetCode *** 38. Count and Say
- leetcode 38. Count and Say
- LeetCode-38. Count and Say
- LeetCode 38. Count and Say
- LeetCode 38. Count and Say
- Leetcode - 38. Count and Say
- LeetCode 38. Count and Say
- Leetcode 38. Count and Say
- HDOJ一只小蜜蜂...
- HDU1051 Wooden Sticks
- Extjs基本知识
- OC-RunTime运行时技术的总结具体代码实现
- IT资讯--------抓取各个博客上的文章
- 38. Count and Say【E】【79】【leetcode】
- 微信商户发放红包接口调试经验总结
- C# 中线程资源访问互斥量
- android自定义一个带进度条的button
- android提高进程优先级的若干方法
- 单元测试一NUnit
- 克服VR眩晕之帧数:提升UE4内容实时渲染效率
- Android创建组合控件
- hadoop伪分布式ha框架搭建