LeetCode 38. Count and Say
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问题
https://leetcode.com/problems/count-and-say/
解法
模拟法， n=100都会超时。
class Solution {public: string countAndSay(int n) { string ret; ret.push_back('1'); for (int i=2; i<=n; ++i){ string now; int cnt =1; for (int j=1; j< ret.size(); ++j) { if (ret[j] != ret[j-1]) { now.append(to_string(cnt)); now.push_back(ret[j-1]); cnt = 1; }else cnt++; } now.append(to_string(cnt)); now.push_back(ret[ret.size()-1]); ret = now; } return ret; }};int 转 string to_string
string 转 int stoi
0 0
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