CodeForces 624A - Save Luke

因为tv1 + tv2 + d <= L,可得答案

#include <cstdio>#include <iomanip>#include <iostream>using namespace std;int main(){double d, l, v1, v2;cin >> d >> l >> v1 >> v2;cout << setprecision(7) << (l - d) / (v1 + v2) <<endl;return 0;}