【杭电-oj】-3188-Just A Triangle
来源:互联网 发布:淘宝价格不一样买哪家 编辑:程序博客网 时间:2024/05/18 19:45
Problem Description
This is an easy problem, just for you to warm up.
Give you three edges of a triangle. Can you tell me which kind of triangle it stands for?
If it’s a right triangle(直角三角形), please output “good”. If it’s a isosceles triangle(等腰三角形), please output “perfect”. Otherwise, please output “just a triangle”. You may suppose the input is legal.
Give you three edges of a triangle. Can you tell me which kind of triangle it stands for?
If it’s a right triangle(直角三角形), please output “good”. If it’s a isosceles triangle(等腰三角形), please output “perfect”. Otherwise, please output “just a triangle”. You may suppose the input is legal.
Input
The first line contains an integer t means the number of test cases.
The each case contains three integers a, b, c in a line which stands for the length of the three edges.
(0 <a, b, c < 300).
The each case contains three integers a, b, c in a line which stands for the length of the three edges.
(0 <a, b, c < 300).
Output
For each case, output the answer in one line.
Sample Input
43 4 52 2 3 1 4 44 6 3
Sample Output
goodperfectperfectjust a triangle
#include<stdio.h>int main(){int n;scanf("%d",&n);while(n--){int a,b,c;scanf("%d%d%d",&a,&b,&c);if(((a==b)&&(a!=c)&&(b!=c))||((a==c)&&(a!=b)&&(c!=b)||(b==c)&&(a!=b)&&(a!=c))){printf("perfect\n");}else if((a*a==b*b+c*c)||(b*b==a*a+c*c)||(c*c==a*a+b*b)){printf("good\n");}elseprintf("just a triangle\n");}return 0;}
0 0
- 【杭电-oj】-3188-Just A Triangle
- 杭电3188 Just A Triangle
- HDOJ 3188 Just A Triangle
- HDU 3188 Just A Triangle JAVA 实现
- HDU 3188 Just A Triangle (水)
- HDU 3188 Just A Triangle [Ad Hoc]
- HDU3188:Just A Triangle
- Just A Triangle
- HDU3188-Just A Triangle
- Just A Triangle
- Just a Numble HDU杭电2117
- hdu-3088-Just A Triangle
- hdu1.2.7 Just A Triangle
- HDU3188 Just A Triangle【水题】
- 1408191710-hd-Just A Triangle.cpp
- 杭电hdu 1698 just a hook 线段树
- HDU--杭电1698--Just a Hook--线段树
- 杭电OJ 1002 A+B
- Online learning 的一些简单认识
- 组织领导层在信息化建设中需要解决的问题
- 打包与压缩
- vim常用命令收集
- BitmapData.draw 绘制透明区域
- 【杭电-oj】-3188-Just A Triangle
- bzoj 4243: 交朋友 bfs
- 进程控制
- hdoj--A Heavy Rainy Day(贪心好题)
- log4j配置信息
- 数据库基础学习-了解DBMS
- android中MVP模式的小案例(一)
- 7CSS动画-2D、3D转换,过滤,动画,多列以及用多列实现瀑布流
- 15电气郄慧敏vb作业715个数的大小排序