HDU3188 Just A Triangle【水题】
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Just A Triangle
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2862 Accepted Submission(s): 2028
Problem Description
This is an easy problem, just for you to warm up.
Give you three edges of a triangle. Can you tell me which kind of triangle it stands for?
If it’s a right triangle(直角三角形), please output “good”. If it’s a isosceles triangle(等腰三角形), please output “perfect”. Otherwise, please output “just a triangle”. You may suppose the input is legal.
InputGive you three edges of a triangle. Can you tell me which kind of triangle it stands for?
If it’s a right triangle(直角三角形), please output “good”. If it’s a isosceles triangle(等腰三角形), please output “perfect”. Otherwise, please output “just a triangle”. You may suppose the input is legal.
The first line contains an integer t means the number of test cases.
The each case contains three integers a, b, c in a line which stands for the length of the three edges.
(0 <a, b, c < 300).
OutputThe each case contains three integers a, b, c in a line which stands for the length of the three edges.
(0 <a, b, c < 300).
For each case, output the answer in one line.
Sample Input43 4 52 2 3 1 4 44 6 3
goodperfectperfectjust a triangle
HDU 2009-11 Programming Contest
问题链接:HDU3188 Just A Triangle。
问题简述:参见上文。
问题分析:(略)
程序说明:(略)题记:(略)
AC的C++语言程序如下:
/* HDU3188 Just A Triangle */#include <iostream>using namespace std;int main(){ int t, a, b, c; cin >> t; while(t--) { cin >> a >> b >> c; if(a == b || b == c || a == c) cout << "perfect" << endl; else if(a * a + b * b == c * c || b * b + c * c == a * a || a * a + c * c == b * b) cout << "good" << endl; else cout << "just a triangle" << endl; } return 0;}
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