leetCode之旅（14）-Number of 1 Bits

题目描述：

Write a function that takes an unsigned integer and returns the number of ’1’ bits it has (also known as the Hamming weight).

For example, the 32-bit integer ’11’ has binary representation 00000000000000000000000000001011, so the function should return 3.

Credits:
Special thanks to @ts for adding this problem and creating all test cases.

Subscribe to see which companies asked this question ##

思路分析：

给定一个无符号整数。求整它转化为二进制以后，里面的1的个数

代码：

public class Solution {

// you need to treat n as an unsigned valuepublic int hammingWeight(int n) {    //用来计数    int count = 0;    for(int i = 0;i < 32;i++){        if((n&1) != 0){            count++;        }        n = n>>1;    }    return count;}

} ##