A. Triangle

A. Triangle

time limit per test

2 seconds

memory limit per test

64 megabytes

input

standard input

output

standard output

At a geometry lesson Bob learnt that a triangle is called right-angled if it is nondegenerate and one of its angles is right. Bob decided to draw such a triangle immediately: on a sheet of paper he drew three points with integer coordinates, and joined them with segments of straight lines, then he showed the triangle to Peter. Peter said that Bob's triangle is not right-angled, but is almost right-angled: the triangle itself is not right-angled, but it is possible to move one of the points exactly by distance 1 so, that all the coordinates remain integer, and the triangle become right-angled. Bob asks you to help him and find out if Peter tricks him. By the given coordinates of the triangle you should find out if it is right-angled, almost right-angled, or neither of these.

Input

The first input line contains 6 space-separated integers x1,?y1,?x2,?y2,?x3,?y3 — coordinates of the triangle's vertices. All the coordinates are integer and don't exceed 100 in absolute value. It's guaranteed that the triangle is nondegenerate, i.e. its total area is not zero.

Output

If the given triangle is right-angled, output RIGHT, if it is almost right-angled, output ALMOST, and if it is neither of these, outputNEITHER.

Sample test(s)

input

0 0 2 0 0 1

output

RIGHT

input

2 3 4 5 6 6

output

NEITHER

input

-1 0 2 0 0 1

output

ALMOST

v退化三角形和三角形的判断

#include<iostream>
#include<cstring>
#include<algorithm>
#include<cstdlib>
#include<vector>
#include<cmath>
#include<stdlib.h>
#include<iomanip>
#include<list>
#include<deque>
#include<map>
#include <stdio.h>
#include <queue>
#include <stack>
#define maxn 10000+5
#define ull unsigned long long
#define ll long long
#define reP(i,n) for(i=1;i<=n;i++)
#define rep(i,n) for(i=0;i<n;i++)
#define cle(a) memset(a,0,sizeof(a))
#define mod 90001
#define PI 3.141592657
#define INF 1<<30
const ull inf = 1LL << 61;
const double eps=1e-5;

using namespace std;

bool cmp(int a,int b){
    return a>b;
}
pair<int,int >p[4];
int dir[4][2]={1,0,0,1,0,-1,-1,0};
int line(int a,int b,int c,int d){
return (a-c)*(a-c)+(d-b)*(d-b);
}
int arr[3];
int judge(int x1,int y1,int x2,int y2,int x3,int y3){
if(x1==x2&&y1==y2)return 0;
if(x2==x3&&y2==y3)return 0;
if(x1==x3&&y1==y3)return 0;
 arr[0]=line(x1,y1,x2,y2);
 arr[1]=line(x1,y1,x3,y3);
 arr[2]=line(x2,y2,x3,y3);
 sort(arr,arr+3);
if(arr[2]==arr[1]+arr[0]) 
return 1;
return 0;
}

int main()
{
//freopen("in.txt","r",stdin);
//freopen("out.txt","w",stdout);
int x1,y1,x2,y2,x3,y3;
while(cin>>p[1].first>>p[1].second>>p[2].first>>p[2].second>>p[3].first>>p[3].second){
if(judge(p[1].first,p[1].second,p[2].first,p[2].second,p[3].first,p[3].second)){
cout<<"RIGHT";return 0;
}
else{
for(int i=0;i<4;i++){
int nx=p[1].first+dir[i][0];
int ny=p[1].second+dir[i][1];
if(judge(nx,ny,p[2].first,p[2].second,p[3].first,p[3].second)){
cout<<"ALMOST";return 0;
}
}
for(int i=0;i<4;i++){

int nx=p[2].first+dir[i][0];
int ny=p[2].second+dir[i][1];
if(judge(p[1].first,p[1].second,nx,ny,p[3].first,p[3].second)){

cout<<"ALMOST";return 0;
}
}
for(int i=0;i<4;i++){

int nx=p[3].first+dir[i][0];
int ny=p[3].second+dir[i][1];
if(judge(p[1].first,p[1].second,p[2].first,p[2].second,nx,ny)){
cout<<"ALMOST";return 0;
}
}
}
cout<<"NEITHER";
}
return0;
}