不支持输入Emoji表情的EditText

import android.content.Context;import android.text.Editable;import android.text.Selection;import android.text.Spannable;import android.text.TextWatcher;import android.util.AttributeSet;import android.view.Gravity;import android.widget.EditText;import android.widget.Toast;public class NoEmojiEditText extends EditText {// 输入表情前的光标位置private int cursorPos;// 输入表情前EditText中的文本private String inputAfterText;// 是否重置了EditText的内容private boolean resetText;private Context mContext;public NoEmojiEditText(Context context) {super(context);this.mContext = context;initEditText();}public NoEmojiEditText(Context context, AttributeSet attrs) {super(context, attrs);this.mContext = context;initEditText();}public NoEmojiEditText(Context context, AttributeSet attrs, int defStyleAttr) {super(context, attrs, defStyleAttr);this.mContext = context;initEditText();}// 初始化edittext 控件private void initEditText() {addTextChangedListener(mTextWatcher);}private TextWatcher mTextWatcher = new TextWatcher() {@Overridepublic void beforeTextChanged(CharSequence s, int start, int before,int count) {if (!resetText) {cursorPos = getSelectionEnd();// 这里用s.toString()而不直接用s是因为如果用s，// 那么，inputAfterText和s在内存中指向的是同一个地址，s改变了，// inputAfterText也就改变了，那么表情过滤就失败了inputAfterText = s.toString();}}@Overridepublic void onTextChanged(CharSequence s, int start, int before,int count) {try {if (!resetText) {if (count >= 2) {// 表情符号的字符长度最小为2CharSequence input = s.subSequence(cursorPos, cursorPos+ count);if (containsEmoji(input.toString())) {resetText = true;Toast toast = Toast.makeText(mContext,"不支持输入Emoji表情符号", Toast.LENGTH_SHORT);toast.setGravity(Gravity.CENTER, 0, 0);toast.show();// 是表情符号就将文本还原为输入表情符号之前的内容setText(inputAfterText);CharSequence text = getText();if (text instanceof Spannable) {Spannable spanText = (Spannable) text;Selection.setSelection(spanText, text.length());}}}} else {resetText = false;}}catch (Exception e){}}@Overridepublic void afterTextChanged(Editable editable) {}};/** * 检测是否有emoji表情 *  * @param source * @return */private boolean containsEmoji(String source) {int len = source.length();for (int i = 0; i < len; i++) {char codePoint = source.charAt(i);if (!isEmojiCharacter(codePoint)) { // 如果不能匹配,则该字符是Emoji表情return true;}}return false;}/** * 判断是否是Emoji *  * @param codePoint *            比较的单个字符 * @return */private boolean isEmojiCharacter(char codePoint) {return (codePoint == 0x0) || (codePoint == 0x9) || (codePoint == 0xA)|| (codePoint == 0xD)|| ((codePoint >= 0x20) && (codePoint <= 0xD7FF))|| ((codePoint >= 0xE000) && (codePoint <= 0xFFFD))|| ((codePoint >= 0x10000) && (codePoint <= 0x10FFFF));}}