UVA - 488 Triangle Wave

Triangle Wave

Time Limit: 3000MS Memory Limit: Unknown 64bit IO Format: %lld & %llu

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Description

 Triangle Wave 

In this problem you are to generate a triangular wave form according to a specified pair of Amplitude and Frequency.

Input and Output

The input begins with a single positive integer on a line by itself indicating the number of the cases following, each of them as described below. This line is followed by a blank line, and there is also a blank line between two consecutive inputs.

Each input set will contain two integers, each on a separate line. The first integer is the Amplitude; the second integer is the Frequency.

For each test case, the output must follow the description below. The outputs of two consecutive cases will be separated by a blank line.

For the output of your program, you will be printing wave forms each separated by a blank line. The total number of wave forms equals the Frequency, and the horizontal ``height'' of each wave equals the Amplitude. The Amplitude will never be greater than nine.

The waveform itself should be filled with integers on each line which indicate the ``height'' of that line.

NOTE: There is a blank line after each separate waveform, excluding the last one.

Sample Input

132

Sample Output

12233322112233322
1
分析：
给出波的振幅和平率，用数字绘制出波形图。
水。
代码：
#include<iostream>#include<stdio.h>using namespace std;int main(){    int n, a, f;    cin >> n;    int cas = 0;    while( n --)    {        if( cas ++) printf("\n");        cin >> a >> f;        while( f -- )        {            for(int i = 1; i <= a; i ++)            {                for( int j = 0; j < i; j ++)                    cout << i;                cout << endl;            }            for(int i = a-1; i >= 1; i --)            {                for( int j = 0; j < i; j ++)                    cout << i;                cout << endl;            }            if( f > 0) cout << endl;        }    }    return 0;}