hdu 1076 An Easy Task

An Easy Task

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 19908    Accepted Submission(s): 12725

Problem Description

Ignatius was born in a leap year, so he want to know when he could hold his birthday party. Can you tell him?

Given a positive integers Y which indicate the start year, and a positive integer N, your task is to tell the Nth leap year from year Y.

Note: if year Y is a leap year, then the 1st leap year is year Y.

 

Input

The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains two positive integers Y and N(1<=N<=10000).

 

Output

For each test case, you should output the Nth leap year from year Y.

 

Sample Input

32005 251855 122004 10000

 

Sample Output

2108190443236
Hint
We call year Y a leap year only if (Y%4==0 && Y%100!=0) or Y%400==0.
 

 

Author

Ignatius.L

 

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Y 开始以后的第N个闰年

闰年为能被4整除不能被100整除 或者被400整除

#include <stdio.h>int main(){int ncase;scanf("%d",&ncase);while(ncase--){int year,n;scanf("%d %d",&year,&n);for(int i=year;;i++){if((i%4==0&&i%100)||i%400==0)n--;if(n==0){printf("%d\n",i);break;}}}return 0;}