Find The Multiple

Description

Given a positive integer n, write a program to find out a nonzero multiple m of n whose decimal representation contains only the digits 0 and 1. You may assume that n is not greater than 200 and there is a corresponding m containing no more than 100 decimal digits.

Input

The input file may contain multiple test cases. Each line contains a value of n (1 <= n <= 200). A line containing a zero terminates the input.

Output

For each value of n in the input print a line containing the corresponding value of m. The decimal representation of m must not contain more than 100 digits. If there are multiple solutions for a given value of n, any one of them is acceptable.

Sample Input

26190

Sample Output

10100100100100100100
111111111111111111
题意：找出任意一个由0和1组成的数，而且是n的倍数。unsigned __int64可以存下结果，循环深度<20;
两条搜索路径---t*10;t*10+1;
#include<iostream>#include<cstdio>#include<cstring>#include<algorithm>using namespace std;bool vis;int n;void dfs(unsigned __int64 x,int n,int k){if(vis) return;if(x%n==0){printf("%I64u\n",x);vis=true;return;}if(k==19) return;dfs(x*10,n,k+1);dfs(x*10+1,n,k+1);}int main(){while(scanf("%d",&n)){if(n==0) break;vis=false;dfs(1,n,0);}return 0;}