CodeForces - 282A Bit++ （水）

CodeForces - 282A

Bit++

Time Limit: 1000MS Memory Limit: 262144KB 64bit IO Format: %I64d & %I64u

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Description

The classic programming language of Bitland is Bit++. This language is so peculiar and complicated.

The language is that peculiar as it has exactly one variable, called x. Also, there are two operations:

• Operation ++ increases the value of variable x by 1.
• Operation -- decreases the value of variable x by 1.

A statement in language Bit++ is a sequence, consisting of exactly one operation and one variable x. The statement is written without spaces, that is, it can only contain characters "+", "-", "X". Executing a statement means applying the operation it contains.

A programme in Bit++ is a sequence of statements, each of them needs to be executed. Executing a programme means executing all the statements it contains.

You're given a programme in language Bit++. The initial value of x is 0. Execute the programme and find its final value (the value of the variable when this programme is executed).

Input

The first line contains a single integer n(1 ≤ n ≤ 150) — the number of statements in the programme.

Next n lines contain a statement each. Each statement contains exactly one operation (++ or --) and exactly one variable x (denoted as letter «X»). Thus, there are no empty statements. The operation and the variable can be written in any order.

Output

Print a single integer — the final value of x.

Sample Input

Input

1++X

Output

1

Input

2X++--X

Output

0

Source

Codeforces Round #173 (Div. 2)

/题意：++表示自增1，--表示自减1

给你n个字符串，让你输出这n个字符串最后的计算结果。

#include<stdio.h>#include<string.h>#include<algorithm>#include<iostream>using namespace std;int judge(char *s){int l=strlen(s);for(int i=0;i<l;i++){if(s[i]=='+') return 1;if(s[i]=='-') return -1;}return 0;}char s[20];int main(){int n;while(scanf("%d",&n)!=EOF){int cnt=0;while(n--){scanf("%s",s);cnt+=judge(s);}printf("%d\n",cnt);}return 0;}