【CodeForces 282A】Bit++(水~)
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The classic programming language of Bitland is Bit++. This language is so peculiar and complicated.
The language is that peculiar as it has exactly one variable, called x. Also, there are two operations:
- Operation ++ increases the value of variablex by 1.
- Operation -- decreases the value of variablex by 1.
A statement in language Bit++ is a sequence, consisting of exactly one operation and one variablex. The statement is written without spaces, that is, it can only contain characters "+", "-", "X". Executing a statement means applying the operation it contains.
A programme in Bit++ is a sequence of statements, each of them needs to be executed. Executing a programme means executing all the statements it contains.
You're given a programme in language Bit++. The initial value of x is 0. Execute the programme and find its final value (the value of the variable when this programme is executed).
The first line contains a single integer n(1 ≤ n ≤ 150) — the number of statements in the programme.
Next n lines contain a statement each. Each statement contains exactly one operation (++ or--) and exactly one variable x (denoted as letter «X»). Thus, there are no empty statements. The operation and the variable can be written in any order.
Print a single integer — the final value of x.
1++X
1
2X++--X
0
题目大意:自增自减
思路:这种大水题我还wa了一发,想抽死自己,想复杂了,以为最后一个如果是x++的话输出x自增之前的值,结果,hh
#include<iostream> #include<cstdio>using namespace std;int main(){ int n,x=0; string s; cin>>n; while(n--){ cin>>s; if(s[1]=='+') x++; else x--; } cout<<x<<endl; return 0;}
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