HDU 1002 A + B Problem II -- java大法好

A + B Problem II

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 306140    Accepted Submission(s): 59153

Problem Description

I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

 

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

 

Output

For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.

 

Sample Input

21 2112233445566778899 998877665544332211

 

Sample Output

Case 1:1 + 2 = 3Case 2:112233445566778899 + 998877665544332211 = 1111111111111111110

 

import java.math.BigInteger;import java.util.Scanner;public class Main {    public static void main(String[] args) {        BigInteger a,b;        int t;        Scanner cin = new Scanner(System.in);        t = cin.nextInt();        for(int i=1;i<=t;i++){            System.out.println("Case"+" "+i+":");            a = cin.nextBigInteger();            b = cin.nextBigInteger();            if(i<t){                System.out.println(a+" + "+b+" = "+a.add(b));                System.out.println();            }            else{                System.out.println(a+" + "+b+" = "+a.add(b));            }        }    }}