leetcode——268——Missing Number
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Given an array containing n distinct numbers taken from
0, 1, 2, ..., n
, find the one that is missing from the array.For example,
Given nums = [0, 1, 3]
return 2
.
Note:
Your algorithm should run in linear runtime complexity. Could you implement it using only constant extra space complexity?
class Solution {public: int missingNumber(vector<int>& nums) { int n = nums.size(); int expect = (n+1) * n / 2; for(int i = 0; i < n; i ++) expect -= nums[i]; return expect; }};
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