leetcode——268——Missing Number

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Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array.

For example,
Given nums = [0, 1, 3] return 2.

Note:
Your algorithm should run in linear runtime complexity. Could you implement it using only constant extra space complexity?


class Solution {public:    int missingNumber(vector<int>& nums) {        int n = nums.size();        int expect = (n+1) * n / 2;        for(int i = 0; i < n; i ++)            expect -= nums[i];        return expect;    }};

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