51Nod－1016－水仙花数 V2

水仙花数是指一个 n 位数 ( n≥3 )，它的每个位上的数字的 n 次幂之和等于它本身。（例如：1^3 + 5^3 + 3^3 = 153，1634 = 1^4 + 6^4 + 3^4 + 4^4）。
给出一个整数M，求 >= M的最小的水仙花数。
Input
一个整数M（10 <= M <= 10^60）
Output
输出>= M的最小的水仙花数，如果没有符合条件的水仙花数，则输出：No Solution
Input示例
300
Output示例
370

一道賊变态的题，如果按常规出牌，绝对做不出来，必然会超时，或者说，我肯定是做不成的。
但是如果投机取巧，那么这就是一道很简单的题，虽然它数据范围高达60位，但是水仙花数却是有限的，只有89个，所以，我们完全可以打表做题。那么剩下的问题就出现了，这些水仙花数是啥？

想知道这些数都是啥，可以选择两种手段，第一暴力解题，获得数据，但是我想这也忒复杂了，虽然是暴力解题，但是依然存在很多问题，就算你写出来代码，想获得所有的水仙花数依然需要很长很长时间等待哦，毕竟运算量惊人。
于是我只好选择第二种办法了，找度娘喽……

这是水仙花数……

01234567891533703714071634820894745474892727930845488341741725421081898008179926315246780502467805188593477146511208472335975534494836912985153467930777432164049650321640496514002839422542678290603447086356794938855060682693916578942045919142811644033596743382817693913704338281769391371218971425876120753564159420896413235875699062250035151784154330750503932895829844431870324498128791164624869492927388592808882663105425988599693916128468643043731391252449177399146038697307218876968411229162888582787969489305407447140527907865009977052567814283612813213192294633983545259010403169193594317408800593806529302372218845148544789789603687523931366443004156935009315504753342145015390888941553242162893771850669378370690799595547598864438037069079959554759886443814422095118095899619457938121204998563613372405438066121270696006801314328439376128851796696487777842012787174650464499531377631639254177265453171792792366489765146076406129719803726148730891900817413625427999501273474019008174136254279995012734741238667164355239759803903692951145037275765491025924292050346192789045714296069758063623663923090926826161903075096953389151733350999778224930872510396277218670996100153879010063413297699018670996100153879010063413297699111227632853293725415928229002045931263936951710379032894780720147839212679937780272278566303885594196922121916721962543412156973580360996601912815792078366059955099770545296129367115132219018763992565095597973971522400115132219018763992565095597973971522401

看着好爽啊，这么长……

接下来要考虑的问题就是比大小，这也好解决，位数不同的比位数，相同的再逐位比大小。大概就是这个样子吧。剩下的就没有什么难点了。

代码（C）：

#include <stdio.h>#include <string.h>int compare(char *a, char *b, int len){    for (int i = 0; i < len; i++)    {        if (b[i] > a[i])        {            return 1;        }        else if (b[i] < a[i])        {            return 0;        }    }    return 1;}int main(int argc, const char * argv[]){    char NarNum[89][60] = {"0","1","2","3","4","5","6","7","8","9","153","370","371","407","1634","8208","9474","54748","92727","93084","548834","1741725","4210818","9800817","9926315","24678050","24678051","88593477","146511208","472335975","534494836","912985153","4679307774","32164049650","32164049651","40028394225","42678290603","44708635679","49388550606","82693916578","94204591914","28116440335967","4338281769391370","4338281769391371","21897142587612075","35641594208964132","35875699062250035","1517841543307505039","3289582984443187032","4498128791164624869","4929273885928088826","63105425988599693916","128468643043731391252","449177399146038697307","21887696841122916288858","27879694893054074471405","27907865009977052567814","28361281321319229463398","35452590104031691935943","174088005938065293023722","188451485447897896036875","239313664430041569350093","1550475334214501539088894","1553242162893771850669378","3706907995955475988644380","3706907995955475988644381","4422095118095899619457938","121204998563613372405438066","121270696006801314328439376","128851796696487777842012787","174650464499531377631639254","177265453171792792366489765","14607640612971980372614873089","19008174136254279995012734740","19008174136254279995012734741","23866716435523975980390369295","1145037275765491025924292050346","1927890457142960697580636236639","2309092682616190307509695338915","17333509997782249308725103962772","186709961001538790100634132976990","186709961001538790100634132976991","1122763285329372541592822900204593","12639369517103790328947807201478392","12679937780272278566303885594196922","1219167219625434121569735803609966019","12815792078366059955099770545296129367","115132219018763992565095597973971522400","115132219018763992565095597973971522401"};    int NarNumLen;    char num[60];    scanf("%s", num);    int NumLen = (int)strlen(num);    for (int i = 0; i < 89; i++)    {        NarNumLen = (int)strlen(NarNum[i]);        if ((NumLen == NarNumLen && compare(num, NarNum[i], NumLen)) || NumLen < NarNumLen)        {            printf("%s\n", NarNum[i]);            return 0;        }    }    puts("No Solution");    return 0;}