第12周-项目1（3）

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问题及代码：
/*Copyright (c)2016,烟台大学计算机与控制工程学院*All rights reserved.*文件名称：main.cpp*作    者：王艺霖*完成日期：2016年5月17日*版 本 号：v1.0*问题描述：定义一个定义完整的类（是可以当作独立的产品发布，成为众多项目中的“基础工程”）。这样的类在(2)的基础上，扩展+、-、*、/运算符的功能，使之能与dou ble型数据进行运算。设Complex c; double d; c+d和d+c的结果为“将d视为实部为d的复数同c相加”，其他-、*、/运算符类似。                           *输入描述：*输出描述：*/#include <iostream>using namespace std;class Complex{public:   Complex(){real=0;imag=0;}   Complex(double r,double i){real=r; imag=i;}    friend Complex operator+(Complex &c1, Complex &c2);    friend Complex operator+(double d1, Complex &c2);    friend Complex operator+(Complex &c1, double d2);    friend Complex operator-(Complex &c1, Complex &c2);    friend Complex operator-(double d1, Complex &c2);    friend Complex operator-(Complex &c1, double d2);    friend Complex operator*(Complex &c1, Complex &c2);    friend Complex operator*(double d1, Complex &c2);    friend Complex operator*(Complex &c1, double d2);    friend Complex operator/(Complex &c1, Complex &c2);    friend Complex operator/(double d1, Complex &c2);    friend Complex operator/(Complex &c1, double d2);    void display();private:    double real;    double imag;};//复数相加：(a+bi)+(c+di)=(a+c)+(b+d)i.Complex operator+(Complex &c1, Complex &c2){    Complex c;    c.real=c1.real+c2.real;    c.imag=c1.imag+c2.imag;    return c;}Complex operator+(double d1, Complex &c2){    Complex c(d1,0);    return c+c2;}Complex operator+(Complex &c1, double d2){    Complex c(d2,0);    return c1+c;}//复数相减：(a+bi)-(c+di)=(a-c)+(b-d)i.Complex operator-(Complex &c1, Complex &c2){    Complex c;    c.real=c1.real-c2.real;    c.imag=c1.imag-c2.imag;    return c;}Complex operator-(double d1, Complex &c2){    Complex c(d1,0);    return c-c2;}Complex operator-(Complex &c1, double d2){    Complex c(d2,0);    return c1-c;}//复数相乘：(a+bi)(c+di)=(ac－bd)+(bc+ad)i.Complex operator*(Complex &c1, Complex &c2){    Complex c;    c.real=c1.real*c2.real-c1.imag*c2.imag;    c.imag=c1.imag*c2.real+c1.real*c2.imag;    return c;}Complex operator*(double d1, Complex &c2){    Complex c(d1,0);    return c*c2;}Complex operator*(Complex &c1, double d2){    Complex c(d2,0);    return c1*c;}//复数相除：(a+bi)/(c+di)=(ac+bd)/(c^2+d^2) +(bc-ad)/(c^2+d^2)iComplex operator/(Complex &c1, Complex &c2){    Complex c;    c.real=(c1.real*c2.real+c1.imag*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag);    c.imag=(c1.imag*c2.real-c1.real*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag);    return c;}Complex operator/(double d1, Complex &c2){    Complex c(d1,0);    return c/c2;}Complex operator/(Complex &c1, double d2){    Complex c(d2,0);    return c1/c;}void Complex::display(){    cout<<"("<<real<<","<<imag<<"i)"<<endl;}int main(){    Complex c1(3,4),c2(5,-10),c3;    double d=11;    cout<<"c1=";    c1.display();    cout<<"c2=";    c2.display();    cout<<"d="<<d<<endl<<endl;    c3=c1+c2;    cout<<"c1+c2=";    c3.display();    cout<<"c1+d=";    (c1+d).display();    cout<<"d+c1=";    (d+c1).display();    c3=c1-c2;    cout<<"c1-c2=";    c3.display();    cout<<"c1-d=";    (c1-d).display();    cout<<"d-c1=";    (d-c1).display();    c3=c1*c2;    cout<<"c1*c2=";    c3.display();    cout<<"c1*d=";    (c1*d).display();    cout<<"d*c1=";    (d*c1).display();    c3=c1/c2;    cout<<"c1/c2=";    c3.display();    cout<<"c1/d=";    (c1/d).display();    cout<<"d/c1=";    (d/c1).display();    return 0;}
运行结果：
学习心得：
数学知识都忘了啊！！！
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