acm 2016/5/18 hpu15级练习 A

A - Petya and Java

Time Limit:2000MS     Memory Limit:262144KB     64bit IO Format:%I64d & %I64u

Submit Status Practice CodeForces 66A

Description

Little Petya has recently started attending a programming club. Naturally he is facing the problem of choosing a programming language. After long considerations he realized that Java is the best choice. The main argument in favor of choosing Java was that it has a very large integer data type, called BigInteger.

But having attended several classes of the club, Petya realized that not all tasks require using the BigInteger type. It turned out that in some tasks it is much easier to use small data types. That's why a question arises: "Which integer type to use if one wants to store a positive integer n?"

Petya knows only 5 integer types:

1) byte occupies 1 byte and allows you to store numbers from  - 128 to 127

2) short occupies 2 bytes and allows you to store numbers from  - 32768 to 32767

3) int occupies 4 bytes and allows you to store numbers from  - 2147483648 to 2147483647

4) long occupies 8 bytes and allows you to store numbers from  - 9223372036854775808 to 9223372036854775807

5) BigInteger can store any integer number, but at that it is not a primitive type, and operations with it are much slower.

For all the types given above the boundary values are included in the value range.

From this list, Petya wants to choose the smallest type that can store a positive integer n. Since BigInteger works much slower, Peter regards it last. Help him.

Input

The first line contains a positive number n. It consists of no more than 100 digits and doesn't contain any leading zeros. The number ncan't be represented as an empty string.

Please, do not use %lld specificator to read or write 64-bit integers in C++. It is preffered to use cout (also you may use %I64d).

Output

Print the first type from the list "byte, short, int, long, BigInteger", that can store the natural number n, in accordance with the data given above.

Sample Input

Input

127

Output

byte

Input

130

Output

short

Input

123456789101112131415161718192021222324

题意：给一个数据（很长），判断它的数据类型。

做了这题才知道自己以前对strcmp函数并没有真正理解！

strcmp:用于字符串的比较，从左到右，知道遇到不同字符或'\0'停止。例如：abcd b 则b大，abcd acdef 则abcd大。

所以题中比较不同长度字符串时，用len 记录长度直接比较即可，然后相同长度用strcmp 比较。

#include <cstdio>#include <cstring>int main(){char str[110];int len;while(~scanf("%s",str)){len=strlen(str);if(len<3||(len==3&&strcmp(str,"127")<=0))printf("byte\n");else if(len<5||(len==5&&strcmp(str,"32767")<=0))printf("short\n");else if(len<10||(len==10&&strcmp(str,"2147483647")<=0))printf("int\n");else if(len<19||(len==19&&strcmp(str,"9223372036854775807")<=0))printf("long\n");else printf("BigInteger\n");}return 0;}