acm 2016/5/18 hpu15级练习 C

D - Flea travel

Time Limit:2000MS     Memory Limit:262144KB     64bit IO Format:%I64d & %I64u

Submit Status Practice CodeForces 75A

Description

Can you imagine our life if we removed all zeros from it? For sure we will have many problems.

In this problem we will have a simple example if we removed all zeros from our life, it's the addition operation. Let's assume you are given this equation a + b = c, where a and b are positive integers, and c is the sum of a and b. Now let's remove all zeros from this equation. Will the equation remain correct after removing all zeros?

For example if the equation is 101 + 102 = 203, if we removed all zeros it will be 11 + 12 = 23 which is still a correct equation.

But if the equation is 105 + 106 = 211, if we removed all zeros it will be 15 + 16 = 211 which is not a correct equation.

Input

The input will consist of two lines, the first line will contain the integer a, and the second line will contain the integer b which are in the equation as described above (1 ≤ a, b ≤ 10⁹). There won't be any leading zeros in both. The value of c should be calculated as c = a + b.

Output

The output will be just one line, you should print "YES" if the equation will remain correct after removing all zeros, and print "NO" otherwise.

Sample Input

Input

101102

Output

YES

Input

105106

Output

NO

题解：题意题目说的很清楚了。先算出c=a+b,然后用数组依次存放a b c 非0的值，计算出去0后a b c的新值a1 b1 c1,c1=a1+b1,

若c=c1 则输出YES。否则输出NO。

#include <cstdio>int main(){long long a,b,c,a1,b1,c1;int s1[10],s2[10],s3[10];while(~scanf("%lld",&a)){scanf("%lld",&b);c=a+b;int m=0,n=0,k=0;while(a){if(a%10!=0){s1[m]=a%10;m++;}a=a/10;}while(b){if(b%10!=0){s2[n]=b%10;n++;}b=b/10;}while(c){if(c%10!=0){s3[k]=c%10;k++;}c=c/10;}a1=0;b1=0;c1=0;for(int i=m-1;i>=0;i--)a1=a1*10+s1[i]; for(int i=n-1;i>=0;i--)b1=b1*10+s2[i];for(int i=k-1;i>=0;i--)c1=c1*10+s3[i];if(a1+b1==c1)printf("YES\n");elseprintf("NO\n");}return 0;}