【一天一道LeetCode】#64. Minimum Path Sum.md
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一天一道LeetCode
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(一)题目
Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.
Note: You can only move either down or right at any point in time.
(二)解题
题目大意:求从m*n的矩阵的左上角走到右下角的所有路径中,路径上的值加起来最小的路径。
思路可以参考:【一天一道LeetCode】#62. Unique Paths &&【一天一道LeetCode】#63. Unique Paths II
class Solution {public: int minPathSum(vector<vector<int>>& grid) { int row = grid.size(); int col = grid[0].size(); vector<vector<int>> path = grid; //path纪录当前点到右下角点的路径和最小值 //对矩阵进行改造,可以避免考虑越界 vector<int> temp(col,2147483647); path.push_back(temp); for(int i = 0 ; i < row ; i++) { path[i].push_back(2147483647); } for(int i = row-1 ; i >=0 ; i--) for(int j = col-1 ; j>=0;j--) { if (i==row-1&&j==col-1) continue;//终点直接跳过 if(path[i][j] ==grid[i][j]) { path[i][j] +=min(path[i+1][j],path[i][j+1]);//每一点到终点的路径和最小值等一向下和向右走的最小值加上自身 } } return path[0][0]; }};
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