java.lang.IllegalArgumentException: Service Intent must be explicit: Intent { act=xxx}

有些时候我们使用Service的时需要采用隐私启动的方式，但是Android 5.0一出来后，其中有个特性就是Service Intent must be explitict，也就是说从Lollipop开始，service服务必须采用显示方式启动。
而android源码是这样写的（源码位置：sdk/sources/android-21/android/app/ContextImpl.java）：

private void validateServiceIntent(Intent service) {        if (service.getComponent() == null && service.getPackage() == null) {            if (getApplicationInfo().targetSdkVersion >= Build.VERSION_CODES.LOLLIPOP) {                IllegalArgumentException ex = new IllegalArgumentException(                        "Service Intent must be explicit: " + service);                throw ex;            } else {                Log.w(TAG, "Implicit intents with startService are not safe: " + service                        + " " + Debug.getCallers(2, 3));            }        }    }

既然，源码里是这样写的，那么这里有两种解决方法：

1、设置Action和packageName：

参考代码如下：

Intent mIntent = new Intent();mIntent.setAction("XXX.XXX.XXX");//你定义的service的actionmIntent.setPackage(getPackageName());//这里你需要设置你应用的包名context.startService(mIntent);

此方式是google官方推荐使用的解决方法。

在此附上地址供大家参考：http://developer.android.com/goo … tml#billing-service,有兴趣的可以去看看。

2、将隐式启动转换为显示启动：–参考地址：http://stackoverflow.com/a/26318757/1446

public static Intent getExplicitIntent(Context context, Intent implicitIntent) {
// Retrieve all services that can match the given intent
PackageManager pm = context.getPackageManager();
List resolveInfo = pm.queryIntentServices(implicitIntent, 0);
// Make sure only one match was found
if (resolveInfo == null || resolveInfo.size() != 1) {
return null;
}
// Get component info and create ComponentName
ResolveInfo serviceInfo = resolveInfo.get(0);
String packageName = serviceInfo.serviceInfo.packageName;
String className = serviceInfo.serviceInfo.name;
ComponentName component = new ComponentName(packageName, className);
// Create a new intent. Use the old one for extras and such reuse
Intent explicitIntent = new Intent(implicitIntent);
// Set the component to be explicit
explicitIntent.setComponent(component);
return explicitIntent;
}

调用方式如下：

Intent mIntent = new Intent();mIntent.setAction("XXX.XXX.XXX");Intent eintent = new Intent(getExplicitIntent(mContext,mIntent));context.startService(eintent);