c++重载运算符梳理

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c++重载运算符

---by ysmor

重新解释运算符的含义，叫做运算符重载-----c++程序设计P277

不多说了，给代码

#include<iostream>using namespace std;class bign{    public:int x;            int y;            int z;    public:           bign(int a,int b,int c)           {               x=a;               y=b;               z=c;           }//注意用友元函数           friend bign operator + (bign a,bign b);//重定义+           friend bign operator - (bign a,bign b);//重定义-           friend bign operator * (bign a,bign b);//重定义*           friend bign operator / (bign a,bign b);//重定义/           friend istream & operator >> (istream &in,bign &a);//重定义>>           friend ostream & operator << (ostream &out,bign &a);//重定义<<};bign operator + (bign a,bign b){    return bign(a.x+b.x,a.y+b.y,a.z+b.z);}bign operator - (bign a,bign b){    return bign(a.x-b.x,a.y-b.y,a.z-b.z);}bign operator * (bign a,bign b){    return bign(a.x*b.x,a.y*b.y,a.z*b.z);}bign operator / (bign a,bign b){    return bign(a.x/b.x,a.y/b.y,a.z/b.z);}istream & operator >> (istream &in,bign &a){    in>>a.x>>a.y>>a.z;    return in;}ostream & operator << (ostream &out,bign &a){    out<<a.x<<" "<<a.y<<" "<<a.z<<endl;    return out;}int main() {    bign x(0,0,0),y(90,100,908),z(0,0,0);    cin>>x;    z=x+y;    cout<<z<<endl;    z=x-y;    cout<<z<<endl;    z=x*y;    cout<<z<<endl;    z=y/x;    cout<<z<<endl;    system("pause");    return 0;}

输入9 100 2

运行结果

99 200 910-81 0 -906810 10000 181610 1 454请按任意键继续. . .

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