[leetcode] 【字符串】58. Length of Last Word

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example, 
Given s = "Hello World",
return 5.

 

题意

一个字符串里最后一个单词的长度

题解

遍历字符串，计算每个单词的长度，返回最后一个单词长度就行。注意细节即可

 

class Solution {public:    int lengthOfLastWord(string s) {        if(s.size()==0)            return 0;        int n=0;        int cur_n=0;        for(int i=0;i!=s.size();i++)        {            if(s[i]!=' ')                cur_n++;            else             {                if(cur_n!=0)                    n=cur_n;                cur_n=0;            }                        }        if(cur_n!=0)            n=cur_n;        return n;    }};