10300 - Ecological Premium

这题目奇奇怪怪的，除掉了在乘回去…这是要考浮点数转整数这个知识点吗？反正我没有除，直接 premium = size*degree.

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题目：

German farmers are given a premium depending on the conditions at their farmyard. Imagine the following simplified regulation: you know the size of each farmer’s farmyard in square meters and the number of animals living at it. We won’t make a difference between different animals, although this is far from reality. Moreover you have information about the degree the farmer uses environment-friendly equipment and practices, expressed in a single integer greater than zero. The amount of money a farmer receives can be calculated from these parameters as follows. First you need the space a single animal occupies at an average. This value (in square meters) is then multiplied by the parameter that stands for the farmer’s environment-friendliness, resulting in the premium a farmer is paid per animal he owns. To compute the final premium of a farmer just multiply this premium per animal with the number of animals the farmer owns.
Input
The first line of input contains a single positive integer n (< 20), the number of test cases. Each test case starts with a line containing a single integer f (0 < f < 20), the number of farmers in the test case. This line is followed by one line per farmer containing three positive integers each: the size of the farmyard in square meters, the number of animals he owns and the integer value that expresses the farmers environment-friendliness. Input is terminated by end of file. No integer in the input is greater than 100000 or less than 0.
Output
For each test case output one line containing a single integer that holds the summed burden for Ger- many’s budget, which will always be a whole number. Do not output any blank lines.
Sample Input
3
5
111
222
333
234
892
3
918
6 12 1 811
3
10 30 40 985
100 1000 70
Sample Output
38 86 7445

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代码：

#include <stdio.h>int main() {    int n;    scanf("%d", &n);    for (int i = 0; i < n; ++i) {        int f, totalBurden = 0;        scanf("%d", &f);        for (int j = 0; j < f; ++j) {            int sm, an, degree;            scanf("%d%d%d", &sm, &an, &degree);            totalBurden += sm * degree;        }        printf("%d\n", totalBurden);    }    return 0;}