488 - Triangle Wave

啊哈！又做出一题！
这题主要是格式问题：要求第一行之前没有换行，之后每两个waves之间都有换行，然后最后一行也没有换行，于是可以把new line和每一个wave绑定：new line＋wave的顺序输出；
如果是第一行：n == 0&&f==0，就只输出wave。

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题目：

In this problem you are to generate a triangular wave form according to a specified pair of Amplitude and Frequency.

Input and Output

The input begins with a single positive integer on a line by itself indicating the number of the cases following, each of them as described below. This line is followed by a blank line, and there is also a blank line between two consecutive inputs.

Each input set will contain two integers, each on a separate line. The first integer is the Amplitude; the second integer is the Frequency.

For each test case, the output must follow the description below. The outputs of two consecutive cases will be separated by a blank line.

For the output of your program, you will be printing wave forms each separated by a blank line. The total number of wave forms equals the Frequency, and the horizontal “height” of each wave equals the Amplitude. The Amplitude will never be greater than nine.

The waveform itself should be filled with integers on each line which indicate the “height” of that line.

NOTE: There is a blank line after each separate waveform, excluding the last one.

Sample Input

1

3
2

Sample Output

1
22
333
22
1

1
22
333
22
1

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代码：

#include <stdio.h>int main() {    int N, A, F;    scanf("%d", &N);    for (int n = 0; n < N; ++n) {        scanf("%d%d", &A, &F);        for (int f = 0; f < F; ++f) {            //输出case n的一个wave            if (n == 0 && f == 0) {            }            else                printf("\n");            for (int i = 1; i <= A; ++i) {                for (int j = 1; j <= i; ++j)                    printf("%d", i);                printf("\n");            }            for (int i = A - 1; i >= 1; --i) {                for (int j = 1; j <= i; ++j)                    printf("%d", i);                printf("\n");            }        }    }    return 0;}