UVA - 1588 Kickdown
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UVA - 1588 Kickdown
题目大意:给出两个长度不一定相同且每列高度为 1 或 2 的长条,将它们放入一个高度为 3 的容器,求最短容器长度。
解题思路:一个一个匹配 超过3的就不可以 然后左右移动上面的 取最小的
#include<iostream>#include<cstring>#include<cstdio>int max(int x, int y) { if (x >= y) return x; else return y;}int min(int x, int y) { if (x <= y) return x; else return y;}int main () { bool f; char a[105],b[105]; while (scanf("%s%s", a, b) != EOF ) { int la = strlen(a),lb = strlen(b),l = 0,ll = 0; for (int i = 0; i < la ;i++,l++) { f = 1; for (int j = 0; j < lb && j + i < la; j++) { if ( b[j] == '2' && a[i+j] == '2') { f = 0; break; } } if (f) { break; } } l = max(la, lb + l); for (int i = 0; i < lb; i++,ll++) { f = 1; for (int j = 0; j < la && j + i < lb; j++) { if ( a[j] == '2' && b[i+j] == '2') { f = 0; break; } } if (f) { break; } } ll = max(lb ,la + ll); printf("%d\n", min(ll,l)); memset(a, 0, sizeof(a)); memset(b, 0, sizeof(b)); }}
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