137. Single Number II LeetCode
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Use Map
public class Solution { public int singleNumber(int[] nums) { Map<Integer,Integer> map = new HashMap<Integer,Integer>(); int len = nums.length; int ans = 0; for (int i = 0; i < len; i++){ int count = 1; if (!map.containsKey(nums[i])) { map.put(nums[i], count); } else map.put(nums[i], (map.get(nums[i]) + 1)); } for (Map.Entry<Integer,Integer> entry : map.entrySet()){ Integer k = entry.getValue(); if (k != 3) { ans = entry.getKey(); break; } } return ans; }}
It contains the for loop. Map.Entry<Integer,Integer> make the traversal.
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