UVA - 327 Evaluating Simple C Expressions
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题目大意:根据 ++、– 的性质计算,a = 1,b = 2……z = 26。输出计算结果和计算后各字母的值。
解题思路:暴力模拟。每碰到一个字母,检查该字母前后是否存在前缀,若存在,将改字母对应的值 +1 或 -1,找到字母前的一个符号 + 或 -,进行对应计算,接着检查该字母是否存在后缀,若存在,将改字母对应的值 +1 或 -1。输出即可。注意自增符号前缀和后缀的计算顺序是不同的,有点难处理。
#include<iostream>#include<cstdio>#include<cstdlib>#include<cstring>#include<cmath>using namespace std;char tmp[1000];char str[1000];char ch[30][2];int sum, tag;int cmp(const void*a, const void*b) { return strcmp((char*)a, (char*)b);}int before(int i) { if (i > 1 && str[i-1] == str[i-2]) { if (str[i-1] == '-') ch[tag][1] -= 1; if (str[i-1] == '+') ch[tag][1] += 1; str[i-1] = str[i-2] = ' '; return 1; }return 0;}int after(int i) { int t = 0; if (str[i+1] == str[i+2]) { if (str[i+1] == '+') t = 1; if (str[i+1] == '-') t = -1; str[i+1] = str[i+2] = ' '; }return t;}int main() { while (gets(tmp)) { printf("Expression: %s\n", tmp); sum = 0; int len = 0; for (int i = 0; i < strlen(tmp); i++) { if (tmp[i] == ' ') continue; str[len++] = tmp[i]; } tag = 0; for (int i = 0; i < len; i++) { if (str[i] >= 'a' && str[i] <= 'z') { ch[tag][0] = str[i]; ch[tag][1] = str[i]; before(i); int j = i; while (j > 0 && str[j] != '+' && str[j] != '-') j--; if (str[j] == '-') sum -= ch[tag][1] - 'a' + 1; else sum += ch[tag][1] - 'a' + 1; ch[tag][1] += after(i); tag++; } } printf(" value = %d\n", sum); qsort(ch, tag, sizeof(ch[0]), cmp); for (int i = 0; i < tag; i++) printf(" %c = %d\n", ch[i][0], ch[i][1] - 'a' + 1); }return 0;}
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