做一个GPSCar类,要求继承Car类,并实现GPS接口

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要求:
1.GPS定义getLocation()方法;
2.Car定义name,speed成员变量 并实现 getCar()方法输出车的名字和速度
3.GPSCar类继承Car并实现GPS接口并重写getLocation(),
返回车的坐标(GPSCar.speed,GPSCar.speed).
重写Car的getCar()方法,除了输出父类的getCar()而且输出getLocation(),

package gps;

public class Car {
 private String name;
 private int speed;
 public String getName() {
  return name;
 }
 public void setName(String name) {
  this.name = name;
 }
 public int getSpeed() {
  return speed;
 }
 public void setSpeed(int speed) {
  this.speed = speed;
 }
public Car(){
 
}
public void getCar(){
 System.out.println("车名:"+this.getName()+"速度"+this.getSpeed());
}
}

 

-------------------------------------------------

package gps;

public interface GPS {
 
 public void getlocation();

}

 

---------------------------------------------------

package gps;

import java.util.Scanner;

public class GPSCar extends Car implements GPS {
 public static void main(String[] args) {
  Car gpscar = new GPSCar();

  Scanner sc = new Scanner(System.in);

  System.out.println("输入车名称:");

  gpscar.setName(sc.nextLine());

  System.out.println("输入车速度:");

  gpscar.setSpeed(sc.nextInt());

  sc.close();

  gpscar.getCar();

  System.out.println();
 }

 @Override
 public void getlocation() {
  System.out.println(this.getSpeed() + ";  " + this.getSpeed());
 }

 public void getCar() {
  super.getCar();
  this.getlocation();

 }

}

 

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