tjut 2824
来源:互联网 发布:sql中minus 编辑:程序博客网 时间:2024/06/06 20:36
#include<iostream>#include<cstring>const int MAXN=3000000+10;using namespace std;int E[MAXN],prime[MAXN];bool visit[MAXN];void Eorue(){ memset(visit, false, sizeof(visit)); for(int i = 2; i <= MAXN; i++) { if(!visit[i]) { prime[++prime[0]] = i; E[i] = i - 1; } for(int j = 1; j <= prime[0] && prime[j] * i <= MAXN; j++) { visit[prime[j]*i] = true; if(i % prime[j] == 0) { E[i*prime[j]] = E[i] * prime[j]; break; } else E[i*prime[j]] = E[i] * (prime[j] - 1); } }}int main(){ int a,b; Eorue(); while(scanf("%d%d",&a,&b)!=EOF){ long long ans=0; for(int i=a;i<=b;i++){ ans+=(long long)E[i]; } printf("%lld\n",ans); } return 0;}
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