LeetCode | Convert Sorted Array to Binary Search Tree
来源:互联网 发布:2016年nba西部决赛数据 编辑:程序博客网 时间:2024/06/05 15:53
Given an array where elements are sorted in ascending order, convert it to a height balanced BST.
首先需要明确一点,如何选择根节点使得左右平衡?
必须要求选择中间的数,这样使得整个数组被划分成为两部分,并且左右大小差距不超过1
于是我们可以利用二分的思想,传入start和end代表需要访问到的数组里面的 节点数量。
一次AC
class Solution {public: TreeNode* sortedArrayToBST(vector<int>& nums) { int n=nums.size(); return generate(nums,0,n-1); } TreeNode* generate(vector<int>& nums,int start,int end){ int n=nums.size(); if(start>end) return NULL; //获取二者中间位置的数作为 int mid=(start+end)/2; TreeNode* node=new TreeNode(nums[mid]); node->left=generate(nums,start,mid-1); node->right=generate(nums,mid+1,end); return node; }};
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