【poj1274】 The Perfect Stall

来源:互联网 发布:matlab定义空矩阵 编辑:程序博客网 时间:2024/05/16 16:08

http://poj.org/problem?id=1274 (题目链接)

题意:懒得写了

Solution
  二分图匹配裸题。注意清空数组。

代码:

// poj3020#include<algorithm>#include<iostream>#include<cstdlib>#include<cstring>#include<cstdio>#include<cmath>#define LL long long#define inf 2147483640#define Pi 3.1415926535898#define free(a) freopen(a".in","r",stdin),freopen(a".out","w",stdout);using namespace std;const int maxn=500;struct edge {int next,to;}e[maxn<<2];int head[maxn],p[maxn],vis[maxn],cnt,n,m;void insert(int u,int v) {    e[++cnt].to=v;e[cnt].next=head[u];head[u]=cnt;}bool find(int x) {    for (int i=head[x];i;i=e[i].next) if (!vis[e[i].to]) {            vis[e[i].to]=1;            if (p[e[i].to]==0 || find(p[e[i].to])) {                p[e[i].to]=x;                return 1;            }        }    return 0;}int main() {    while (scanf("%d%d",&n,&m)!=EOF) {        for (int i=1;i<=n;i++) p[i]=head[i]=0;        cnt=0;        for (int i=1;i<=n;i++) {            int x;scanf("%d",&x);            for (int j=1;j<=x;j++) {                int t;scanf("%d",&t);                insert(i,t);            }        }        int ans=0;        for (int i=1;i<=n;i++) {            for (int j=1;j<=n;j++) vis[j]=0;            if (find(i)) ans++;        }        printf("%d\n",ans);    }    return 0;}
0 0
原创粉丝点击