Leetcode 88 Merge Sorted Array

Given two sorted integer arrays nums1 andnums2, merge nums2 into nums1 as one sorted array.

Note:
You may assume that nums1 has enough space (size that is greater or equal tom + n) to hold additional elements from nums2. The number of elements initialized innums1 and nums2 are m and n respectively.

题目链接：https://leetcode.com/problems/merge-sorted-array/

题目大意：将两个有序数组nums1和nums2合并到nums1中，保证nums1的空间足够

题目分析：将nums1的值向后移n位，为了防止越界从最后一位向前移，然后两个指针比较并移动即可

public class Solution {    public void merge(int[] nums1, int m, int[] nums2, int n) {        for(int i = m - 1; i >= 0; i--) {            nums1[i + n] = nums1[i];        }        int ptr1 = n, ptr2 = 0, ptr = 0;        while(ptr1 < m + n && ptr2 < n) {            if(nums1[ptr1] < nums2[ptr2]) {                nums1[ptr ++] = nums1[ptr1 ++];            }            else {                nums1[ptr ++] = nums2[ptr2 ++];            }        }        while(ptr1 < m + n) {            nums1[ptr ++] = nums1[ptr1 ++];        }        while(ptr2 < n) {            nums1[ptr ++] = nums2[ptr2 ++];        }    }}