UVA 11205 The broken pedometer
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UVA 11205 The broken pedometer
题目大意:给出几行数字组合,求出至少取几列可以分辨出不同行
解题思路:刚刚开始学子集生成,方法比较笨,位向量法生成子集,去二进制数,然后排序,求相邻的数是否都不相同
#include <stdio.h>#include <iostream>#include <string.h>#include <math.h>using namespace std;int m, l;int num[100][100];int num2[100];int com[100];int mi;int cmd(const void *a, const void *b) { return *(int*)a - *(int*)b;}void sol(int a, int b) { if(m == 1) { mi = 0; return; } if(a == l && b == 0) return; if(a == l) { memset(com, 0, sizeof(com)); for(int i = 0; i < l; i++) if(num2[i] == 1) { for(int j = 0; j < m; j++) com[j] = com[j] + num[j][i] * pow(2, i); } qsort(com, m, sizeof(int), cmd); for(int i = 1; i < m; i++) { if(com[i] == com[i-1]) return; } if(b < mi) mi = b; return; } num2[a] = 0; sol(a+1, b); num2[a] = 1; sol(a+1, b+1);}int main() { int n; cin >> n; while(n--) { memset(num, 0, sizeof(num)); memset(num2, 0, sizeof(num2)); cin >> l; cin >> m; for(int i = 0; i < m; i++) { for(int j = 0; j < l; j++) cin >> num[i][j]; } mi = l; sol(0, 0); cout << mi << endl; } return 0;}
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- UVa 11205 The broken pedometer
- uva 11205 - The broken pedometer
- uva 11205 - The broken pedometer
- UVa 11205 - The broken pedometer
- uva 11205 - The broken pedometer
- UVa 11205 - The broken pedometer
- UVA 11205 The broken pedometer
- uva 11205 The Broken Pedometer
- uva 11205 The broken pedometer
- uva 11205 - The broken pedometer
- UVa 11205 - The broken pedometer
- UVA 11205 The broken pedometer
- UVa 11205 - The broken pedometer
- UVA 11205 - The broken pedometer
- UVa-11205-The broken pedometer
- UVA - 11205 The broken pedometer
- UVA - 11205 The broken pedometer
- uva 11205 The broken pedometer
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