Linkedin第三方登录集成(android)

来源：互联网发布：网络自制综艺节目排行编辑：程序博客网时间：2024/05/17 06:37

1.需要在linkedin开发者那里注册应用。 https://www.linkedin.com/developer/apps/new
添加后，需要填写应用包名和package Hash码
这里写图片描述
具体方式可自行百度或者参考 http://blog.csdn.net/u010838555/article/details/39851863
2.下载linkedin的sdk，https://developer.linkedin.com/downloads#androidsdk并以module的方式集成到自己的项目中
3.获取手机端的授权详情：https://developer.linkedin.com/docs/android-sdk-auth

public class MainActivity extends Activity {    @Override    protected void onCreate(Bundle savedInstanceState) {            // Store a reference to the current activity         final Activity thisActivity = this;        LISessionManager.getInstance(getApplicationContext()).init(thisActivity, buildScope(), new AuthListener() {            @Override            public void onAuthSuccess() {                // Authentication was successful.  You can now do                // other calls with the SDK.            }            @Override            public void onAuthError(LIAuthError error) {                // Handle authentication errors            }        }, true);    }}// Build the list of member permissions our LinkedIn session requiresprivate static Scope buildScope() {    return Scope.build(Scope.R_BASICPROFILE, Scope.W_SHARE);}@Overrideprotected void onActivityResult(int requestCode, int resultCode, Intent data) {    // Add this line to your existing onActivityResult() method    LISessionManager.getInstance(getApplicationContext()).onActivityResult(this, requestCode, resultCode, data);}

4.获取授权成功后，获取用户信息 url：https://api.linkedin.com/v1/people/~ 获取全部信息 https://api.linkedin.com/v1/people/~:(firstName,lastName,id,picture-url)?format=json 获取指定信息
可参考linkedin的官方文档 https://developer.linkedin.com/docs/signin-with-linkedin

String url  ="https://api.linkedin.com/v1/people/~:(firstName,lastName,id,picture-url)?format=json";         APIHelper apiHelper = APIHelper.getInstance(getApplicationContext());                apiHelper.getRequest(getApplicationContext(), url, new ApiListener() {                    @Override                    public void onApiSuccess(ApiResponse apiResponse) {                        // Success!                        LogUtils.e(TAG, "apiResponse" + apiResponse.toString());                    }                    @Override                    public void onApiError(LIApiError liApiError) {                        // Error making GET request!                        LogUtils.e(TAG, " Error making GET request!");                    }

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