BZOJ 2157: 旅游

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题意如往常一般省略啦。
这道题感觉比前几道有了点意思,关于维护其实差不多。
但是这题的权值是在边上,所以我们弄多一个点在两点中间表示边权 也就是:x->++id->y
取反的话注意一下 max=-min min=-max就好 这个不难懂吧?
代码:

#include<map>#include<cmath>#include<queue>#include<string>#include<cstdio>#include<vector>#include<cstdlib>#include<cstring>#include<algorithm>#define inf 1000000000#define me(a,x) memset(a,x,sizeof a)#define cp(a,x) memcpy(a,x,sizeof a)#define N 20010using namespace std;typedef long long LL;int fa[N<<1],n,m,c[N<<1][2],st[N<<1],w[N<<1];int e[N],mx[N<<1],mn[N<<1],sum[N<<1];bool rev[N<<1],turn[N<<1];bool Rt(int x){    if(c[fa[x]][0]==x || c[fa[x]][1]==x)return 0;    return 1;}void pushup(int x){    int l=c[x][0],r=c[x][1];    sum[x]=sum[l]+sum[r]+w[x];    mx[x]=max(mx[l],mx[r]);    mn[x]=min(mn[l],mn[r]);    if(x>n)mx[x]=max(mx[x],w[x]);    if(x>n)mn[x]=min(mn[x],w[x]);}void rever(int x){    if(!x)return;    sum[x]=-sum[x],w[x]=-w[x];    swap(mx[x],mn[x]);    mx[x]=-mx[x],mn[x]=-mn[x];    turn[x]^=1;}void pushdown(int x){    int l=c[x][0],r=c[x][1];    if(turn[x])    {        turn[x]=0;        rever(l); rever(r);    }    if(rev[x])    {        rev[x]=0,rev[l]^=1,rev[r]^=1;        swap(c[x][0],c[x][1]);    }}void rotate(int x){    int y=fa[x],z=fa[y],a=c[y][1]==x,b=c[z][1]==y,g=c[x][!a];    if(!Rt(y))c[z][b]=x;    fa[g]=y,c[y][a]=g;    fa[y]=x,c[x][!a]=y;    fa[x]=z;    pushup(y); pushup(x);}void splay(int x){    int top=0,i;    for(i=x;!Rt(i);i=fa[i])st[++top]=i;    st[++top]=i;    for(i=top;i;i--)pushdown(st[i]);    while(!Rt(x))    {        int y=fa[x],z=fa[y],a=c[y][1]==x,b=c[z][1]==y;        if(!Rt(y))        {            if(a==b)rotate(y);            else rotate(x);        }        rotate(x);    }}void access(int x){    int last=0;    while(x)    {        splay(x);        c[x][1]=last;        pushup(x);        last=x,x=fa[x];    }}void make_root(int x){    access(x); splay(x);    rev[x]^=1;}void split(int x,int y){    make_root(x);    access(y); splay(y);}void link(int x,int y){    make_root(x); fa[x]=y;}void cut(int x,int y){    split(x,y);    fa[x]=c[y][0]=0;}int main(){    int i,x,y,p;    char ch[5];    scanf("%d",&n);    for(i=0;i<=n;i++) mn[i]=inf,mx[i]=-inf;    int id=n;    for(i=1;i<n;i++)    {        scanf("%d%d%d",&x,&y,&p); x++,y++;        e[i]=++id;        link(x,id); link(y,id);        w[id]=sum[id]=mx[id]=mn[id]=p;    }    scanf("%d",&m);    while(m--)    {        scanf("%s%d%d",ch,&x,&y); x++,y++;        if(ch[0]=='C')        {            x--,y--;   splay(e[x]);            w[e[x]]=y; pushup(e[x]);        }        if(ch[0]=='N')            split(x,y),rever(y);        if(ch[0]=='S')            split(x,y),printf("%d\n",sum[y]);        if(ch[1]=='A')            split(x,y),printf("%d\n",mx[y]);        if(ch[1]=='I')            split(x,y),printf("%d\n",mn[y]);    }    return 0;}
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