[leetcode] Implement pow(x, n). Subscribe to see which companies asked this question
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Implement pow(x, n).
要注意n<0的情况。
class Solution {public: double myPow(double x, int n) { if(n<0) return 1/power(x,-n); else return power(x,n); } double power(double x, int n){ double res; if(n==0) return 1; double half = power(x,n/2); if(n%2==0) return half*half; else return x*half*half; }};
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