pat 乙 1010. 一元多项式求导

#include<iostream>using namespace std;int coff[10000],expo[10000];int size1,size2=0;int main(){//int flag=1;int num=1;int a;while(cin>>a){if(num%2!=0){coff[size1++]=a;}else{expo[size2++]=a;}num++;}if(expo[0]!=0){cout<<coff[0]*(expo[0])<<" "<<expo[0]-1;for(int i=1;i<size1;i++){if(expo[i]!=0){cout<<" "<<coff[i]*(expo[i])<<" "<<expo[i]-1;}}}else{cout<<0<<" "<<0;}return 0;}