LeetCode 231,326,342 --Power of Two & Three & Four
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Given an integer, write a function to determine if it is a power of two & three & four.
Two:这几个题，都可以用同一种解法，用当前数一直整除另一个数，一旦无法整除，且余数不为0；则说明不是 2& 3& 4的幂：
<span style="font-size:14px;">public class Solution { public boolean isPowerOfThree(int n) { if(n <= 0) return false; while(n % 3 == 0){ n = n/3; } return n == 1; }}</span>2的幂的另一种解法，减一相与法，如果一个数与减1想与为0 ，则是2的幂数。
<span style="font-size:14px;">public class Solution { public boolean isPowerOfTwo(int n) { return (n & (n-1)) == 0 && n > 0; }}</span> 0 0
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